Hi there!
Recall the following:
k = Coulomb's Constant (Jm/C²)
q = Charge (C)
r = distance between charges (m)
To calculate the electric force between the two charges, we can simply divide by another 'r' (distance):
A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the
cord is then connected to a hanging weight. Calculate the force exerted by the ground on the box (in lb), if the hanging weight is 10.5 lb.
1 answer:
Answer:
The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.
<u>F1 = T- 46, 674.656 gm/s² </u>
Explanation:
<em>Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.</em>
To calculate the force caused by gravity on the basic pulley system we use the following equation:
F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g
∴ F2 = 4762.72g x 9.8 m/s²
= 46, 674.656 gm/s² or 46, 674.656 N
But since this F2 is acting in a downlowrd direction, it would be negative.
Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)
⇒ F1 = T - F2
<u>F1 = T- 46, 674.656 gm/s² </u>
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Answer:
E = 7.334 KeV
Explanation:
given,
initial energy = 60 keV
Δ x = 30 cm
μ(for soft tissue) = 0.7 cm⁻¹ (taken from table)
E = 60 × 0.1224
E = 7.334 KeV
energy of x-ray photon after travelling through 30 cm soft tissue in body is E = 7.334 KeV