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Ray Of Light [21]
3 years ago
10

A cord is attached to the box and run through a pulley directly above the box, so that the cord is vertical. The free end of the

cord is then connected to a hanging weight. Calculate the force exerted by the ground on the box (in lb), if the hanging weight is 10.5 lb.

Physics
1 answer:
Harman [31]3 years ago
4 0

Answer:

The answer is given here would be a simplified equation, seeing as there are some missing variables in the question.

<u>F1 = T- 46, 674.656 gm/s² </u>

Explanation:

<em>Note: Once we have the mass of the second object and/or acceleration of the cord, we can solve for the force of the ground acting on the box.</em>

To calculate the force caused by gravity on the basic pulley system we use the following equation:

F2 = M2 x g; where g= gravitational acceleration (a constant equal to 9.8 m/s²). The mass M2 = 10.5 lb = 4762.72g

∴ F2 = 4762.72g x 9.8 m/s²

= 46, 674.656 gm/s² or 46, 674.656 N

But since this F2 is acting in a downlowrd direction, it would be negative.

Tension of the cord, T = Mass, x × acceleration. ( x is in the pulley diagram)

⇒ F1 = T - F2

<u>F1 = T- 46, 674.656 gm/s² </u>

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Answer:

The average speed is 8.0 km/h

Explanation:

We use the data for the return journey to calculate the distance travelled using the constant velocity equation:

s  =  v  t  =6*4=24km

 

Note I didn't change any units so the answer comes out in kilometres.

Now use the distance and time taken to travel to Guam to find the average speed:

v=st=24/3=8.0km/h

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3 years ago
If a marathon runner averages 9.50 mi/h, how many minutes does it take him or her to run a 26.22-mi marathon?
horsena [70]

Answer: 196 minutes

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3 years ago
A 40.0-mH inductor is connected to a North American electrical outlet (ΔVrms = 120 V, f = 60.0 Hz). Assuming the energy stored i
trasher [3.6K]

Explanation:

It is given that,

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Frequency, f = 60 Hz

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The current flowing through the inductor is given by :

I_t=\dfrac{V_o}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{\sqrt{2} V_{rms}}{X_L}\ (sin\ \omega t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi f L}\ sin(2\pi f t-\dfrac{\pi}{2})

I_t=\dfrac{120\sqrt{2}}{2\pi\times 60\times 40\times 10^{-3}}\ sin(2\pi \times 60\times \dfrac{1}{185})-\dfrac{\pi}{2})    

I_t=\dfrac{120\sqrt2}{15.07}\ sin(2\pi \times 60\times \dfrac{1}{185}-\dfrac{\pi}{2})

I = 0.091 A

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The era of planet formation ended when the remaining hydrogen and helium gas of the solar nebula was swept into interstellar spa
artcher [175]

Answer:

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Explanation:          

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Then, when the star has the necessary pressure and temperature to initiate nuclear reactions in its core, it will be able to emit huge amounts of energy, better known as solar winds. These winds will expel gas (hydrogen and helium) from the Solar System more easily than the rocky and metallic  particles.

Notice that when such event occurs, rocky and gaseous planets were already formed.

       

Key terms:

¹Protostar: A young star.

²Planetesimals: Object formed by many fragments due to the gravitational attraction between them.

5 0
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