The student weighs 108.8 pounds on saturn. 85x2.34=198.9 -90.1 = 108.8
Answer:
a:x=-3
c:x=1
Step-by-step explanation:
The zeros of a function are the values of x for which the value of the function f(x) becomes zero.
In this problem, we have the following function:
Here we want to find the zeros of the function, i.e. the values of x for which
In order to make f(x) equal to zero, either one of the factors 
or 
must be equal to zero.
Therefore, the two zeros can be found by requiring that:
1)
2)
So the correct options are
a:x=-3
c:x=1
1st one : is 1/4 ( subtract 3/8 from both sides and simplify 5/8 - 3/8 to 1/4. )
2nd one : is 1/2 ( subtract 3/4 from both sides, simplify 1/4 - 3/4 to 1/-2, and then multiply both sides by -1 )
3rd one : is 5/6 ( subtract 1/8 from both sides and simplify 23/24 - 1/8 to 5/6).
Answer:
B) (3, –2)
Explanation:
The inequality is y ≤ –x + 1
There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.
I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C.
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign.
Try it in the inequality:
y ≤ –x + 1
–2 ≤ –3 + 1
–2 ≤ –2 yes this checks out.
0.088
Step-by-step explanation:
The total number of balls in the urn is;
8 + 5 = 12
Because the pink balls are 8, then the probability of picking a pink ball from the urn is;
8/12
To get the probability that all 6 balls drawn from the urn are pink, we will use the AND probability rule of the mutually exclusive events which means we’ll multiply the probabilities of each of the six pink balls;
8/12 * 8/12 * 8/12 * 8/12 * 8/12 * 8/12
= 0.088
Learn More:
For more on probabilities check out;
brainly.com/question/11248705
brainly.com/question/1177537
#LearnWithBrainly
