Answer:
  ΔL = 3.82 10⁻⁴ m
Explanation:
This is a thermal expansion exercise
           ΔL = α L₀ ΔT
           ΔT = T_f - T₀
where ΔL is the change in length and ΔT is the change in temperature
Let's reduce the length to SI units
           L₀ = 90.5 mm (1m / 1000 mm) = 0.0905 m
let's calculate
           ΔL = 25.10⁻⁶ 0.0905 (154.6 - (14.4))
           ΔL = 3.8236 10⁻⁴ m
      
using the criterion of three significant figures
           ΔL = 3.82 10⁻⁴ m
 
        
             
        
        
        
Answer:
<em>The force required is 3,104 N</em>
Explanation:
<u>Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = ma
Where a is the acceleration of the object.
On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

Where:
vf is the final speed
vo is the initial speed
a is the acceleration
t is the time
Solving for a:

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:


The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F= 3,104 N
The force required is 3,104 N
 
        
             
        
        
        
Am sorry what can you be more specific