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Paraphin [41]
3 years ago
6

An object with an initial velocity of 27 m/s has a final velocity of 39 m/s after 13 seconds.

Physics
1 answer:
grigory [225]3 years ago
8 0

Answer:

<h3>The answer is 0.92 m/s²</h3>

Explanation:

To find the acceleration of an object given it's initial and final velocity and time taken we use the formula

a =  \frac{v - u}{t}  \\

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question

v = 39 m/s

u = 27 m/s

t = 13 s

We have

a =  \frac{39 - 27}{13}  =  \frac{12}{13}  \\  = 0.923076... \:  \:  \:

We have the final answer as

<h3>0.92 m/s²</h3>

Hope this helps you

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Answer:

C

Explanation:

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You drive your car 3 hrs at an average of 130 km how far did you go
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What’s the name of the “super continent” that broke up about 225 million years ago?
Salsk061 [2.6K]

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Read 2 more answers
The first car has twice the mass of a second car, but only half as much kinetic energy. When both cars increase their speed by 9
kirill [66]

Answer:

Speed of the car 1 =V_1=8.98m/s

Speed of the car 2 =V_2=17.96m/s

Explanation:

Given:

Mass of the car 1 , M₁ = Twice the mass of car 2(M₂)

mathematically,

M₁ = 2M₂

Kinetic Energy of the car 1 = Half the kinetic energy of the car 2

KE₁ = 0.5 KE₂

Now, the kinetic energy for a body is given as

KE =\frac{1}{2}mv^2

where,

m = mass of the body

v = velocity of the body

thus,

\frac{1}{2}M_1V_1^2=0.5\times \frac{1}{2}M_2V_2^2

or

\frac{1}{2}2M_2V_1^2=0.5\times \frac{1}{2}M_2V_2^2

or

2M_2V_1^2=0.5\times M_2V_2^2

or

2V_1^2=0.5\times V_2^2

or

4V_1^2= V_2^2

or

2V_1= V_2  .................(1)

also,

\frac{1}{2}M_1(V_1+9.0)^2=\frac{1}{2}M_2(V_2+9.0)^2

or

\frac{1}{2}2M_2(V_1+9.0)^2=\frac{1}{2}M_2(2V_1+9.0)^2

or

2(V_1+9.0)^2=(2V_1+9.0)^2

or

\sqrt{2}(V_1+9.0)=(2V_1+9.0)

or

(\sqrt{2}V_1+ \sqrt{2}\times 9.0)=(2V_1+9.0)

or

(\sqrt{2}V_1+ 12.72)=(2V_1+9.0)

or

(2V_1-\sqrt{2}V_1)=(12.72-9.0)

or

(0.404V_1)=(3.72)

or

V_1=8.98m/s

and, from equation (1)

V_2=2\times 8.98m/s = 17.96m/s

Hence,

Speed of car 1 =V_1=8.98m/s

Speed of car 2 =V_2=17.96m/s

8 0
3 years ago
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Lifting a piano into a truck is an example of doing negative work. A. True B. False
Elis [28]

Answer:

False

Explanation:

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