An object with an initial velocity of 27 m/s has a final velocity of 39 m/s after 13 seconds.
1 answer:
Answer:
<h3>The answer is 0.92 m/s²</h3>Explanation:
To find the acceleration of an object given it's initial and final velocity and time taken we use the formula
where
v is the final velocity
u is the initial velocity
t is the time taken
a is the acceleration
From the question
v = 39 m/s
u = 27 m/s
t = 13 s
We have
We have the final answer as
<h3>0.92 m/s²</h3>Hope this helps you
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Answer:
(a) -202 m/s²
(b) 198 m
Explanation:
Given data
- Initial speed (v₀): 283 m/s
- Final speed (vf): 0 (rest)
- Time (t): 1.40 s
(a) The acceleration (a) is the change in the speed over the time elapsed.
a = (vf - v₀)/t = (0 - 283 m/s)/ 1.40s = -202 m/s²
(b) We can find the distance traveled (d) using the following kinematic expression.
y = v₀ × t + 1/2 × a × t²
y = 283 m/s × 1.40 s + 1/2 × (-202 m/s²) × (1.40 s)²
y = 198 m
Answer:
Impedance, Z = 107 ohms
Explanation:
It is given that,
Resistance, R = 100 ohms
Inductance,
Capacitance,
Frequency, f = 60 Hz
Voltage, V = 120 V
The impedance of the circuit is given by :
...........(1)
Where
is the capacitive reactance,
is the inductive reactance,
So, equation (1) becomes :
Z = 106.26 ohms
or
Z = 107 ohms
So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.