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Paraphin [41]
3 years ago
6

An object with an initial velocity of 27 m/s has a final velocity of 39 m/s after 13 seconds.

Physics
1 answer:
grigory [225]3 years ago
8 0

Answer:

<h3>The answer is 0.92 m/s²</h3>

Explanation:

To find the acceleration of an object given it's initial and final velocity and time taken we use the formula

a =  \frac{v - u}{t}  \\

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question

v = 39 m/s

u = 27 m/s

t = 13 s

We have

a =  \frac{39 - 27}{13}  =  \frac{12}{13}  \\  = 0.923076... \:  \:  \:

We have the final answer as

<h3>0.92 m/s²</h3>

Hope this helps you

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A circular coil of radius r = 5 cm and resistance R = 0.2 is placed in a uniform magnetic field perpendicular to the plane of th
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Answer:

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

E=-\frac{d}{dt}(BACOS\alpha )\\

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using \pi r^{2} \\ where r is the radius of 5cm or 0.05m

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since we no that the angle is at 0^{0}

we determine the magnitude of the magnetic filed

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V=IR\\R=0.2\\I=\frac{0.000532}{0.2} \\I=0.0026A

I=2.6mA

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