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Aleks [24]
3 years ago
8

In the diagram shown at the right, a 2-foot-wide flower border surrounds the heart-shaped pond. What is the area of the border?

Mathematics
1 answer:
True [87]3 years ago
6 0
The area is 139.02 sq. ft.

This can be broken into two shapes:  a 12 by 12 square and a circle with a diameter of 12.  Adding the 2 ft border increases it to a 14 by 14 square and a circle with a radius of 16 (2 on each side).  

With border:

Area of square = 14*14 = 196
Area of circle = 3.14(8*8) = 200.96

Together = 396.96

Without border:

Area of square = 12*12 = 144
Area of circle = 3.14(6*6) = 113.04

Together = 257.04

This is a difference of 396.96-257.04 = 139.02 sq. ft.
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12.) When rounding to the nearest 10, what is the largest number that will
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Answer:

34 is the answer

plz mark brainliest

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3 years ago
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1- ? divided by 3 = -7 <br> 2- -50 divided by ? =10<br> 3- ? divided by -2 = 10
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3 years ago
Why the systems must have the same solution?system(a)4x-5y=13.....3x+6y=11........system(b) 8x-10y=26.....x-11y=2.........AKA QU
Y_Kistochka [10]
When you add the equations in (a) you get 7x+y=24.

When you subtract the equations in (b) you also get 7x+y=24.

That means to solve both systems you can work with the same equation. However that is not enough. We must have two equivalent equations. We found only one.

Notice however that in the (b) we can take the first equation and divide every term by 2. When we do this we get 4x-5y=13. That’s the first equation in (a).

So both systems can be solved by working with the same two equations. These are 5x-5y=13 and 7x+y=24. And since we have two equations and two unknowns (the number of equations matches the number of variables) there is only one solution — one x and y that would make both systems true — solve both systems.

Basically we showed the systems are equivalent!
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=4%20%5Csqrt%7B40%7D%20%20%2B%207%20%5Csqrt%7B160%7D%20" id="TexFormula1" title="4 \sqrt{40} +
dmitriy555 [2]

Answer:

36\sqrt{10}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals in the expression

\sqrt{40}

= \sqrt{4(10)}

= \sqrt{4} × \sqrt{10} = 2\sqrt{10}

\sqrt{160}

= \sqrt{16(10)}

= \sqrt{16} × \sqrt{10} = 4\sqrt{10}

Thus

4\sqrt{40} + 7\sqrt{160}

= 4 × 2\sqrt{10} + 7 × 4\sqrt{10}

= 8\sqrt{10} + 28\sqrt{10}

= 36\sqrt{10}

5 0
3 years ago
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What are the domain and range of the function f(x) = *x+5?
BartSMP [9]

Answer:

Graphs of inverse functions have a domain and range just like any other graph of a function. The domain of an inverse function is the range of the original, and the range of an inverse function is the domain of an original.

Step-by-step explanation:

6 0
3 years ago
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