Answer:
Explanation:
F = Force
C = Drag coefficient equal for both aircrafts
ρ = Density of air
A = Surface area equal for both aircrafts
v = Velocity
Dividing the above two equations we get
The ratio of the drag forces is
A skier is gliding down a slope at a constant speed. what energy transformation is taking place?
1 answer:
In this process, gravitational potential energy is converting into heat/thermal energy.
In fact, the skier starts at a certain height h, so it has gravitational potential energy equal to
as he slides down, he loses this energy. However, the problem says that the speed of the skier remains constant during the motion, so this energy is not converting into kinetic energy, which remains constant. The only possibility is that a frictional force between the skier and the ice is acting on the skier. When the friction acts, the energy of the skier is converted into motion of the molecules of the ice, heating it, so into thermal energy.
In fact, the skier starts at a certain height h, so it has gravitational potential energy equal to
as he slides down, he loses this energy. However, the problem says that the speed of the skier remains constant during the motion, so this energy is not converting into kinetic energy, which remains constant. The only possibility is that a frictional force between the skier and the ice is acting on the skier. When the friction acts, the energy of the skier is converted into motion of the molecules of the ice, heating it, so into thermal energy.
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B) initial speed (u)=3
final speed (v)=8
time (t)= 10
acceleration (a)=?
v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²
c)displacement (s)=?
1st section of journey
v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters
2nd section of journey
a=0
t=7
u=8
s=?
s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters
56+55= 111 meters
(For graph x axis =time (sec) & y axis= velocity (m/s))
final speed (v)=8
time (t)= 10
acceleration (a)=?
v=u+at
8=3+a(10)
5=10a
a=1/2= 0.5 m/s²
c)displacement (s)=?
1st section of journey
v ²=u ²+2as
8 ²=3 ²+2(0.5)s
64=9+1s
s=55meters
2nd section of journey
a=0
t=7
u=8
s=?
s=ut+1/2at²
s=8(7)+1/2(0)(7 ²)
s=56 meters
56+55= 111 meters
(For graph x axis =time (sec) & y axis= velocity (m/s))