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MakcuM [25]
3 years ago
11

In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the

first light source has a wavelength of 646 nm. Two different interference patterns are observed. If the 9th order bright fringe from the first light source coincides with the 11th order bright fringe from the second light source, what is the wavelength of the light coming from the second monochromatic light source?
Physics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

Explanation:

Let λ be the required wavelength.

Two fringe patterns will be formed on the screen which will overlap each other. Let 9 th bright fringe of first coincides with 11 th bright fringe  of second.

position of 9 the bright fringe of first = 9x 646 x D/d  nm

position of 11 th bright fringe of second pattern = 11 x λ x D/d

now , 9 x 646 = 11 x λ

λ = 9 x 646 / 11 = 528.54 nm.

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4 0
3 years ago
Read 2 more answers
A penny has a mass of 2.50 g, a diameter of 19.55 mm, and a thickness of 1.55 mm. Calculate the density of the material from whi
Dmitry [639]
Density = (mass) divided by (volume)

We know the mass (2.5 g).  We need to find the volume.

The penny is a very short cylinder.
The volume of a cylinder is (π · radius² · height).
The penny's radius is 1/2 of its diameter = 9.775 mm.
The 'height' of the cylinder is the penny's thickness = 1.55 mm.

Volume  =  (π) (9.775 mm)² (1.55 mm)

             =  (π) (95.55 mm²) (1.55 mm)

             =  (π) (148.1 mm³)

             =        465.3 mm³

We know the volume now.  So we could state the density of the penny,
but nobody will understand what we have.  Here it is:

         mass/volume = 2.5 g / 465.3 mm³  =  0.0054 g/mm³  .

Nobody every talks about density in units of ' gram/(millimeter)³ ' .
It's always ' gram / (centimeter)³ '.
So we have to convert our number for the volume.

                         (0.0054  g/mm³)  x  (10 mm / cm)³

                 =      (0.0054 x 1,000)  g/cm³

                 =          5.37  g/cm³  .

This isn't actually very close to what the US mint says for the density
of a penny, but it's in a much better ball park than 0.0054 was.
4 0
3 years ago
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