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mart [117]
3 years ago
10

How much work is done when 0.0080 C is moved through a potential difference of 1.5 V?

Physics
2 answers:
maksim [4K]3 years ago
5 0

Answer:

Work done, W = 0.012 Joules

Explanation:

It is given that,

Charge, q = 0.0080 C

Potential difference, V = 1.5 volts

We need to find the work done. Potential difference is given by work done divided by charged moved. Mathematically, it is given by :

W=q\times V

W=0.0080\times 1.5\ V

W = 0.012 Joules

So, the work done by the charge is 0.012 Joules. Hence, this is the required solution.

qwelly [4]3 years ago
3 0
.012 J is going to be your answer

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You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
Current what can do work in an electric device
Serggg [28]
It could help transport important information
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When atoms are organized in repeating patterns, they generally make a _________. select one of the options below as your answer:
valkas [14]
A. Solid

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4 0
3 years ago
A student was traveling to see his grandmother who lives 15 miles north oh his home he started from rest and maintained a pace o
N76 [4]

Explanation:

Given parameters:

Distance  = 15miles north = 24140.2m

Initial velocity  = 0m/s

Final velocity  = 4m/s

Unknown:

Speed, velocity and acceleration = ?

Solution:

The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.

  Speed  = \frac{distance }{time}  

  The speed of the student is 4m/s

Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;

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Acceleration is the change in velocity with time;

     To find the acceleration, we use

      v²  = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

     4² = 0² + 2x a x 24140.2

       a  = \frac{16}{2 x 24140.2}  = 0.00033m/s²

3 0
2 years ago
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