How much work is done when 0.0080 C is moved through a potential difference of 1.5 V?
2 answers:
Answer:
Work done, W = 0.012 Joules
Explanation:
It is given that,
Charge, q = 0.0080 C
Potential difference, V = 1.5 volts
We need to find the work done. Potential difference is given by work done divided by charged moved. Mathematically, it is given by :
W = 0.012 Joules
So, the work done by the charge is 0.012 Joules. Hence, this is the required solution.
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The propagation errors we can find the uncertainty of a given magnitude is the sum of the uncertainties of each magnitude.
Δm = ∑
Physical quantities are precise values of a variable, but all measurements have an uncertainty, in the case of direct measurements the uncertainty is equal to the precision of the given instrument.
When you have derived variables, that is, when measurements are made with different instruments, each with a different uncertainty, the way to find the uncertainty or error is used the propagation errors to use the variation of each parameter, keeping the others constant and taking the worst of the cases, all the errors add up.
If m is the calculated quantity, x_i the measured values and Δx_i the uncertainty of each value, the total uncertainty is
Δm = ∑ | dm / dx_i | Dx_i
for instance:
If the magnitude is a average of two magnitudes measured each with a different error
m =
Δm = | | Δx₁ + |
| Δx₂
= ½
= ½
Δm = Δx₁ + ½ Δx₂
Δm = Δx₁ + Δx₂
In conclusion, using the propagation errors we can find the uncertainty of a given quantity is the sum of the uncertainties of each measured quantity.
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