Question

What is the solution to this system of equations?

Answer 1

Answer: The system of equations has no solutions.

Step-by-step explanation:

Identify the equation as:

$x + 2y - z=3$   [Equation 1]

$2x -y + 2z=6$    [Equation 2]

$x - 3y + 3z=4$    [Equation 3]

Multiply  [Equation 1]  by -2 and add this to [Equation 2] :

$(-2)(x + 2y - z)=3(-2)$

$\left \{ {{-2x - 4y +2z=-6} \atop {2x -y + 2z=6}} \right.\\ ..........................\\-5y+4z=0$

 Find another equation of two variables: Multiply  [Equation 3]  by -2 and add this to [Equation 2]:

$(-2)(x - 3y + 3z)=4(-2)$  

$\left \{ {{2x -y + 2z=6} \atop {-2x +6y -6z=-8}} \right.\\........................\\5y-4z=-2$

Then you get this new system of equations. When you add them, you get:

$\left \{ {{-5y+4z=0} \atop {5y-4z=-2}} \right.\\..................\\0=-2$

Since the obtained is not possible, the system of equations has no solutions.