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3 years ago

Determine weather the rule represents an exponential function. EASY 40 POINTS

Mathematics

1 answer:

joja [24]3 years ago

5 0

<h3>Answer: Since the independent variable x is not the exponent, y = 3x^3 is <u>not</u> an exponential function (choice D)</h3>

Exponential functions are something like y = 2^x where the variable is in the exponent (ie the exponent isnt a fixed number). What is given here, y = 3x^3, is a cubic function. You can also call this a power function. Power functions are of the form a*x^b, where a & b are constants.

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A group of hikers walks 2 miles east and then 1 mile north. After taking a break, they then hike 4 miles east to their final des

kodGreya [7K]

Answer:

Intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

Step-by-step explanation:

Required vector is consists of the two components

vx= 2+4=6 units and vy= 1 unit and vx ⊥ vy

We will use Pythagorian theorem to find intensity of the vector v

v∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 units

The angle ∡α between vector and east direction we wil find with tanα

tanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

Good luck!!!

7 0

3 years ago

Which number lies halfway between:<br>a) 16 and 38<br>b) 259 and 361<br>1004 and 2 012?<br>

xxTIMURxx [149]

Answer:

Which number lies halfway between:

a) 16 and 38 = 28

b) 259 and 361 =310

1004 and 2012?

=1058

8 0

2 years ago

raph the equation with a diameter that has endpoints at (-3, 4) and (5, -2). Label the center and at least four points on the ci

andreyandreev [35.5K]

Answer:

Equation:

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

The point (0,-5), (0,7), (5,0) and (-7,0)also lie on this circle.

Step-by-step explanation:

We want to find the equation of a circle with a diamterhat hs endpoints at (-3, 4) and (5, -2).

The center of this circle is the midpoint of (-3, 4) and (5, -2).

We use the midpoint formula:

$( \frac{x_1+x_2}{2}, \frac{y_1+y_2,}{2} )$

Plug in the points to get:

$( \frac{ - 3+5}{2}, \frac{ - 2+4}{2} )$

$( \frac{ -2}{2}, \frac{ 2}{2} )$

$( - 1, 1)$

We find the radius of the circle using the center (-1,1) and the point (5,-2) on the circle using the distance formula:

$r = \sqrt{ {(x_2-x_1)}^{2} + {(y_2-y_1)}^{2} }$

$r = \sqrt{ {(5 - - 1)}^{2} + {( - 2- - 1)}^{2} }$

$r = \sqrt{ {(6)}^{2} + {( - 1)}^{2} }$

$r = \sqrt{ 36+ 1 } = \sqrt{37}$

The equation of the circle is given by:

$(x-h)^2 + (y-k)^2 = {r}^{2}$

Where (h,k)=(-1,1) and r=√37 is the radius

We plug in the values to get:

$(x- - 1)^2 + (y-1)^2 = {( \sqrt{37}) }^{2}$

$(x + 1)^2 + (y - 1)^2 = 37$

We expand to get:

${x}^{2} + 2x + 1 + {y}^{2} - 2y + 1 = 37$

${x}^{2} + {y}^{2} + 2x - 2y +2 - 37= 0$

${x}^{2} + {y}^{2} + 2x - 2y - 35= 0$

We want to find at least four points on this circle.

We can choose any point for x and solve for y or vice-versa

When y=0,

${x}^{2} + {0}^{2} + 2x - 2(0) - 35= 0$

${x}^{2} +2x - 35= 0$

$(x - 5)(x + 7) = 0$

$x = 5 \: or \: x = - 7$

The point (5,0) and (-7,0) lies on the circle.

When x=0

${0}^{2} + {y}^{2} + 2(0) - 2y - 35= 0$

${y}^{2} - 2y - 35= 0$

$(y - 7)(y + 5) = 0$

$y = 7 \: or \: y = - 5$

The point (0,-5) and (0,7) lie on this circle.

3 0

3 years ago

Points (3,1) and (1,4) lie on line k. What is the slope of the line that is perpendicular to k?

denis-greek [22]

First we need to find the slope of line k. Using the slope formula, we fill in accordingly: $m= \frac{4-1}{1-3}$ . The slope is -3/2. The slope of a line that is perpendicular to line k will have the opposite sign (so, positive) and will be the reciprocal of the line k's slope (so, 2/3). You could also say, more "mathematically legal", that the product of the slopes of perpendicular lines is -1, but it's easier to just say that they are opposite reciprocals. The slope you're looking for is 2/3. Choice 3 above.

6 0

3 years ago

Plz help<br> and no guessing

Pani-rosa [81]

Multiply 1st equation by 5
-5x + 10y = -20

now you have
-5x + 10y = -20
5x - 10y = 20
---------------------add
0 + 0 = 0
0 = 0

answer
C. the system has infinitely many solutions

6 0

3 years ago

Read 2 more answers