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vazorg [7]
3 years ago
5

A TRAIN TRAVELING AT A CONSTANT RATE OF SPEED COVERS 360 KILOMETERS IN 6 HOURS WHAT IS THE SPEED OF THE TRAIN

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

60kmh

Step-by-step explanation:

in order to answer this, we do some simple division.

360 divided by 6 is 60, so the train is going 60km an hour.

FromTheMoon [43]3 years ago
5 0

Answer:

60 km/hr

Step-by-step explanation:

Speed = distance / time

Speed = 360 km / 6 hr

Speed = 60 km/hr

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Write an inequality that represents the verbal expression. All real numbers less than 74
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3 years ago
How many solutions does the equation 9x-3(x+8)=6x-24
Marina86 [1]
Simplifying
9x + -3(x + 8) = 6x + -24

Reorder the terms:
9x + -3(8 + x) = 6x + -24
9x + (8 * -3 + x * -3) = 6x + -24
9x + (-24 + -3x) = 6x + -24

Reorder the terms:
-24 + 9x + -3x = 6x + -24

Combine like terms: 9x + -3x = 6x
-24 + 6x = 6x + -24

Reorder the terms:
-24 + 6x = -24 + 6x

Add '24' to each side of the equation.
-24 + 24 + 6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
0 + 6x = -24 + 24 + 6x
6x = -24 + 24 + 6x

Combine like terms: -24 + 24 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
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Solving
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7 0
3 years ago
Read 2 more answers
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
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