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ratelena [41]
3 years ago
14

At a certain temperature this reaction follows first-order kinetics with a rate constant of 0.184 s^-1 ? Suppose a vessel contai

ns Cl_2 O_5 at a concentration of 1.16 M. Calculate the concentration of Cl_2 O_5 in the vessel 5.70 seconds later.
Chemistry
1 answer:
meriva3 years ago
6 0

Answer:

0.57 M

Explanation:

rate = change in concentration /time

Initial concentration of Cl2O5 = 1.16 M

Let the concentration of Cl2O5 after 5.70 seconds be y

rate = (1.16 - y)/5.7

The reaction follows a first order

Therefore, rate = ky = 0.184y

0.184y = (1.16 - y)/5.7

0.184y × 5.7 = 1.16 - y

1.0488y + y = 1.16

2.0488y = 1.16

y = 1.16/2.0488 = 0.57 M

Concentration of Cl2O5 after 5.70 seconds is 0.57 M

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Explain how sodium and calcium react with water. explain with equations
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4 0
3 years ago
a chemistry teacher adds 50.0 ml of 1.50 m h2so4 solution to 200 ml of water. What is the concentration of the final solution?
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Explanation:1) Data:

a) Initial solution

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b) Solvent added = 200 ml = 0.200 l

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3) Solution:

a) initial solution:

Clearing moles from the molarity formula: moles = M × V

moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol

b) final solution:

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ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer

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