Question

The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 x 10^23 atoms in 1 mol. How many atoms are present in 48.60 g of Mg?

Answer 1

Atoms of Mg  =  mol  *  L
   
     mol of Mg =  $\frac{MASS}{MOLAR MASS}$
 
                      =  $\frac{48.60 g}{24.30 g / mol}$
    
                      =  2 mol

∴ atoms of Mg  =  2 mol  *  ( 6.02  x  10²³)
                         =  1.204  x  10²⁴