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eduard
4 years ago
12

Does static electricity mean that the charges never move? explain

Physics
1 answer:
olga55 [171]4 years ago
4 0
No it would be completely wrong to assume that static electricity means that the charges never move. Any kind of electricity always involves the movement of electrons. In reality, static electricity is caused by friction or by rubbing electrons from the surfaces of other materials. So the electrons did not get there by current and thus it is called static electricity.
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A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0
3 years ago
Read 2 more answers
Que fracción de luz que llega directa a una lamina de vidrio se refleja en la primera superficie?
Veseljchak [2.6K]

Answer:

unos 40 o30 pienso

Explanation:

7 0
3 years ago
Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft
Solnce55 [7]

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

6 0
3 years ago
What is the terminal velocity of a 6.00-kg mass object in falling with a drag force with a magnitude that depends on speed, v, a
3241004551 [841]

When object reached the terminal speed then its acceleration is zero

So as per Newton's II law we can say

F_{net} = 0

now in that case we can say that net force is zero so here weight of the object is counter balanced by the drag force when it will reach at terminal speed

so we can write

mg - F_d = 0

so here we are given that

F_d = 30

6*9.8 - 30*v = 0

58.8 - 30 *v = 0

v = \frac{58.8}{30}

v = 1.96 m/s

so terminal speed will be nearly 2 m/s

6 0
3 years ago
A closed cylindrical tank of radius 3.5 m and height 2m is made from
Dahasolnce [82]

Explanation:

Total surface area of cylinder:

2\pi \times r(h + r) \\ 2 \times \pi \times 3.5(3.5 + 2) \\ 2\pi \times 19.25 = 120.951317 \\ 120.95  \: {cm}^{2}

sheet of metal required = 120.95 cm^2

3 0
3 years ago
Read 2 more answers
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