Question

12 is produced by the reaction of 0.5235 mol of CuCl2 according to the following equation: 2CuCl2 +4K1—2Cul + 4KCI + 12. What is the mass of the la produced? 66.43 g 33.22 g 132.9 g

Answer 1

Answer:

The mass of I₂ produced is 66.43 g.

Explanation:

In a stoichiometry exercise we follow a series of steps.

Step 1: Write the balanced equation

2 CuCl₂ + 4 KI ⇄ 2 CuI + 4 KCl + I₂

Step 2: Look for the relationship between the data we have and the one we are looking for

According to the balanced equation, when 2 moles of CuCl₂ react 1 mole of I₂ is formed. This is the first relation. Secondly, we know that the molar mass of 253.80 g/mol, that is, every mole of I₂ has a mass of 253.80 g. This is the second relation.

Step 3: Apply relations to the data we have

$0.5235mol(CuCl_{2}).\frac{1mol(I_{2})}{2mol(CuCl_{2})} .\frac{253.80g(I_{2})}{1mol(I_{2})} =66.43g(I_{2})$