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Maksim231197 [3]
3 years ago
11

A small lab cart and one of larger mass collide and rebound off each other. Which of them has the greater average force on it du

ring the collision
They both experience a force of zero.


They both experience the same magnitude of the collision force.


The large cart has greater force on it.


The small cart has greater force on it.
Physics
1 answer:
Elza [17]3 years ago
4 0

When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time

During this contact interval we can say they will exert normal force on each other

This normal force is always equal and opposite on two balls which means this force will follow Newton's III law

It will be same in magnitude but opposite in the direction

So here correct answer would be

<u><em>They both experience the same magnitude of the collision force.</em></u>

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A ball is swung in a horizontal circle at a constant speed. Each circle takes 0.85 seconds to complete and the rope is 0.40 m lo
BaLLatris [955]

Answer:

The centripetal acceleration will be "21.785 m/s²".

Explanation:

The given values are:

Time,

t = 0.85 seconds

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Mass of ball,

m = 0.80 kg

As we know,

⇒ w=\frac{2 \pi}{t}

On substituting the values, we get

⇒      =\frac{2\times 3.14}{0.85}

⇒      = \frac{6.28}{0.85}

⇒      =7.38 \ rad/s^2

The centripetal acceleration will be:

⇒  a=r\times w^2

⇒     =0.40\times (7.38)^2

⇒     =0.40\times 54.46

⇒     =21.785 \ m/s^2

7 0
2 years ago
Please any one need help on this
Romashka [77]

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-- A "rarefaction" is exactly the opposite of a "compression".  It's a place where the wave gets more "<em>rare</em>" ... the wavelength temporarily gets longer, so that several waves get stretched out, and there are fewer of them in some  period of time.  The arrow in the picture points to a rarefaction.

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3 years ago
The voltage in a circuit can be determined from the ____, total resistance, and capacitance
Dmitrij [34]
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A 2.4 mm -diameter copper wire carries a 37 A current (uniform across its cross section). Determine the magnetic field at the su
cluponka [151]

Answer:

Explanation:

We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.

∫B.dl = μ₀ I , B is magnetic field , I is current ,  μ₀ is permeability .

Radius of the wire r = 1.2 x 10⁻³ m

magnetic field B will be circular in shape around the wire. If B is uniform

∫B.dl = B x 2πr  

B x 2πr  = μ₀ I

B = μ₀ I / 2πr

= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³

= 10⁻⁷ x 2x37 / 1.2 x 10⁻³

= 61.67 x 10⁻⁴ T

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aliya0001 [1]

Answer:

Explanation:

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I ∝ 1 /r²  where I is intensity and r is distance from source . If I₁ and I₂ be intensity at distance r₁ and r₂ .

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So intensity will become 16 times less bright .

"16 times " is the answer .

8 0
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