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Maksim231197 [3]
3 years ago
11

A small lab cart and one of larger mass collide and rebound off each other. Which of them has the greater average force on it du

ring the collision
They both experience a force of zero.


They both experience the same magnitude of the collision force.


The large cart has greater force on it.


The small cart has greater force on it.
Physics
1 answer:
Elza [17]3 years ago
4 0

When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time

During this contact interval we can say they will exert normal force on each other

This normal force is always equal and opposite on two balls which means this force will follow Newton's III law

It will be same in magnitude but opposite in the direction

So here correct answer would be

<u><em>They both experience the same magnitude of the collision force.</em></u>

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In a cyclic process, a gas performs 123 J of work on its surroundings per cycle. What amount of heat, if any, transfers into or
Margaret [11]

Answer:

123 J transfer into the gas

Explanation:

Here we know that 123 J work is done by the gas on its surrounding

So here gas is doing work against external forces

Now for cyclic process we know that

\Delta U = 0

so from 1st law of thermodynamics we have

dQ = W + \Delta U

dQ = W

so work done is same as the heat supplied to the system

So correct answer is

123 J transfer into the gas

8 0
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Based upon the information you have learned throughout this module on blood spatter analysis, do you feel that analyzing blood s
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Answer:

I do not think that it is the most reliable way to gain information since it is very hard to do and can be easily messed up. No, I don't think you can charge someone on only evidence from blood spatter, but if there was additional evidence I think that this would definitely help with the case but not on its own, since it doesn’t give you physical evidence about the suspect.

Explanation:

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3 years ago
A tall, cylindrical chimney falls over when its base is ruptured. Treat the chimney as a thin rod of length 53.2 m. At the insta
rusak2 [61]
From an energy balance, we can use this formula to solve for the angular speed of the chimney

ω^2 = 3g / h sin θ

Substituting the given values:
ω^2 = 3 (9.81) / 53.2 sin 34.1
ω^2 = 0.987 /s

The formula for radial acceleration is:
a = rω^2

So,
a = 53.2 (0.987) = 52.494 /s^2

The linear velocity is:
v^2 = ar
v^2 = 52.949 (53.2) = 2816.887

The tangential acceleration is:
a = r v^2
a = 53.2 (2816.887)
a = 149858.378 m/s^2

If the tangential acceleration is equal to g:
g = r^2 3g / sin θ
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7 0
3 years ago
Iodine molecules separates into atoms after absorbing light of 450 nm. If one
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Energy absorbed by each atom :

E (atom) = 2.205 x 10-19 J

Now Bond Energy of each molecule (B) = 3.98 x J

So, for each atom 1.99 x 10-19 J

So now

KE of each atom = E(atom) - B (atom)

= 2.15 x 10-19 J

5 0
3 years ago
An 800-kHz radio signal is detected at a point 8.5 km distant from a transmitter tower. The electric field amplitude of the sign
Temka [501]

Answer:

Explanation:

Given that,

Frequency of radio signal is

f = 800kHz = 800,000 Hz.

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d = 8.5km = 8500m

Electric field amplitude

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The average energy density can be calculated using

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U_E = ½ × 8.85 × 10^-12 × 0.9²

U_E = 3.58 × 10^-12 J/m²

The average electromagnetic energy density is 3.58 × 10^-12 J/m²

6 0
3 years ago
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