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3 years ago

A metal ball has a mass of 2kg and a volume of 6 m3. What is its density

Physics

2 answers:

Lena [83]3 years ago

8 0

Answer: The answer is 333.3333 repeating

Explanation:

Divide the mass by the volume.

Whitepunk [10]3 years ago

7 0

Answer:

Density of the metal ball, $\rho=0.334\ kg/m^3$

Explanation:

It is given that,

Mass of the metal ball, m = 2 kg

Volume of the metal ball, $V=6\ m^3$

We need to find the density of the metal ball. The total mass divided by total volume of an substance is called its density. Its formula is given by :

$\rho=\dfrac{m}{V}$

$\rho=\dfrac{2\ kg}{6\ m^3}$

$\rho=0.334\ kg/m^3$

So, the density of the metal ball is $0.334\ kg/m^3$ . Hence, this is the required solution.

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3 years ago

One uniform ladder of mass 30 kg and 10 m long rests against a frictionless vertical wall and makes an angle of 60o with the flo

yuradex [85]

Answer:

μ = 0.37

Explanation:

For this exercise we must use the translational and rotational equilibrium equations.

We set our reference system at the highest point of the ladder where it touches the vertical wall. We assume that counterclockwise rotation is positive

let's write the rotational equilibrium

W₁ x/2 + W₂ x₂ - fr y = 0

where W₁ is the weight of the mass ladder m₁ = 30kg, W₂ is the weight of the man 700 N, let's use trigonometry to find the distances

cos 60 = x / L

where L is the length of the ladder

x = L cos 60

sin 60 = y / L

y = L sin60

the horizontal distance of man is

cos 60 = x2 / 7.0

x2 = 7 cos 60

we substitute

m₁ g L cos 60/2 + W₂ 7 cos 60 - fr L sin60 = 0

fr = (m1 g L cos 60/2 + W2 7 cos 60) / L sin 60

let's calculate

fr = (30 9.8 10 cos 60 2 + 700 7 cos 60) / (10 sin 60)

fr = (735 + 2450) / 8.66

fr = 367.78 N

the friction force has the expression

fr = μ N

write the translational equilibrium equation

N - W₁ -W₂ = 0

N = m₁ g + W₂

N = 30 9.8 + 700

N = 994 N

we clear the friction force from the eucacion

μ = fr / N

μ = 367.78 / 994

μ = 0.37

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3 years ago

A lightning bolt transfers 6.0 coulombs of charge from a cloud to the ground in 2.0 x 10-3 second. what is the average current d

AlladinOne [14]

The current is defined as the amount of charge transferred through a certain point in a certain time interval:
$I= \frac{Q}{\Delta t}$
where
I is the current
Q is the charge
$\Delta t$ is the time interval

For the lightning bolt in our problem, Q=6.0 C and $\Delta t= 2.0 \cdot 10^{-3}s$ , so the average current during the event is
$I= \frac{Q}{\Delta t} = \frac{6.0 C}{2.0 \cdot 10^{-3} s}=3000 A$

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3 years ago

What is the difference between transverse and longitudinal waves? Transverse waves always have greater frequencies than do longi

Anastasy [175]

Answer:

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3 years ago

3) connect two lamps to a power supply in series and current drawn from the power supply is is. connect the same two lamps in pa

notka56 [123]

The current drawn by the series circuit is(R₁ + R₂)/R₁R₂ times the current drawn by the parallel circuit.

Let the resistance of the two lamps are R₁ and R₂.

Then the equivalent resistance in series combination is: R = R₁ + R₂.

And, the equivalent resistance in parallel combination is:

r = R₁R₂/(R₁ + R₂).

So, if the supply voltage is V,

Then, current drown in series combination; $i_s$ = V/R = V/(R₁ + R₂)

And, current drown in parallel combination; $i_p$ = V/r = V(R₁ + R₂)/R₁R₂

So , $\frac{i_s}{i_p}$ = [ V/(R₁ + R₂)] /[V(R₁ + R₂)/R₁R₂]

= (R₁ + R₂)/R₁R₂

Hence, the ratio of current drawn in series and current drown in parallel is (R₁ + R₂)/R₁R₂. So, he current drawn by the series circuit is(R₁ + R₂)/R₁R₂ times the current drawn by the parallel circuit.

Learn more about electric current here:

brainly.com/question/2264542

#SPJ1

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1 year ago