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2 years ago

Calculate the pressure exerted by a 4000N camel on the sand. The camel’s feet have a

Physics

1 answer:

Harrizon [31]2 years ago

3 0

Answer:

The pressure exerted by camel feet is 2000 N/m².

Step-by-step explanation:

<h3>Solution :</h3>

Here, we have given that ;

Force applied on camel feet = 4000 N
Total area of camel feet = 2 m²

We need to find the pressure exerted by camel feet.

As we know that :

${\longrightarrow{\pmb{\sf{Pressure= \dfrac{Area}{Force}}}}}$

Substituting all the given values in the formula to find the pressure exerted by camel feet.

$\begin{gathered} \begin{array}{l} {\longrightarrow{\sf{Pressure= \dfrac{Area}{Force}}}} \\ \\ {\longrightarrow{\sf{Pressure= \dfrac{4000}{2}}}} \\ \\ {\longrightarrow{\sf{Pressure= \cancel{\dfrac{4000}{2}}}}} \\ \\ {\longrightarrow{\sf{Pressure= 2000 \: N/{m}^{2}}}} \\ \\\star \: \small\underline{\boxed{\sf{\purple{Pressure= 2000 \: N/{m}^{2}}}}} \end{array}\end{gathered}$

Hence, the pressure exerted by camel feet is 2000 N/m².

$\rule{300}{2.5}$

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2 years ago

How fast, in rpm, would a 5.6 kg, 25-cm-diameter bowling ball have to spin to have an angular momentum of 0.26 kgm2/s

solong [7]

Answer:

71 rpm

Explanation:

Given that:

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w = 445.74 / 2π rpm

w = 70.941724

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3 years ago

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Vikentia [17]

The Newton’s law Nikolas would use to come up with this idea is the Third law that states:

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