Answer:
D = 9.9 10⁶ mi
Explanation:
In the exercise they give the expression for maximum viewing distance
D = 2 r h + h²
Ask for this distance for a height of 1100 feet
Let's calculate
D = 2 3960 1100 + 1100²
D = 8.712 10⁶ + 1.21 10⁶
D = 9.92 10⁶ mi
D = 9.9 10⁶ mi
Answer:
B. 10m/s
Explanation:
If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.
Displacement is calculated using Pythagoras theorem.
d² = 8²+6²
d² = 64+36
d² = 100
Square root both sides
√d² = √100
d = 10m/s
Hence the distance of the drone with respect to the ground is 10m/s
Option B is correct
Answer:
the greater the height of an object the *greater* its gravitational potential energy
greater
Answer:
Very easy question
For x-component, we use Fₓ = Fcosα
For y-component, we use Fy = Fsinα
The major problem is with angle α.
Here α = 90+30
Because the angle is measured from +ve X-axis.
By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.
So for further calculation,
Fₓ = Fcos(90+30) = 25(-sin30)
Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"
As it is
Fy = Fsin(90+30) = Fcos30
Fy = 25 (√3 /2) = 25√3/2
......................................................................................