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notka56 [123]
2 years ago
12

The coefficient of static friction between waxed skis and now snow is 0.14. What force will be needed to get a 700 N skier at re

st moving?
A: 28 N
B: 70 N
C: 98 N
D: 980 N
Physics
2 answers:
TiliK225 [7]2 years ago
8 0

Answer:

C. 98 N

Explanation:

The force needed to get the skier at rest moving must be at least equal to the maximum static frictional force acting on the skier, which is given by

F=\mu W

where

\mu = 0.14 is the coefficient of static friction

W = 700 N is the weight of the skier

Substituting into the equation, we find

F=(0.14)(700 N)=98 N

balu736 [363]2 years ago
3 0

Answer:

c

Explanation:

μ = f/N where μ is the coefficient of friction; f is the amount of force that resists motion, and N is the normal force. You must solve for f here so 700 N x .14 = 98 N.

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A person takes a trip, driving with a constant speed of 94.5 km/h except for a 22.0 min rest stop. If the person's average speed
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From the average speed you can fix an equation:

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You know the average speed = 65.1 kg / h, then

65.1 = distance / total time,

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Call t the time treavelling and pass 22 minutes to hours:

65.1 = distance / [t + 22/60] ==> distance = [t + 22/60]*65.1

 
From the constant speed, you can fix a second equation

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94.5 = distance / t ==> distance = 94.5 * t

The distance is the same in both equations, then you have:

[t +22/60] * 65.1 = 94.5 t

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29.4t = 23.87

t = 23.87 / 29.4

t  = 0.812 hours

distance = 94.5 km/h * 0.812 h = 76.7 km

Answers: 1) 0.81 hours, 2) 76.7 km


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3 years ago
Question 14 of 25
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the answer is sueist

Explanation:

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The car bounces off and moves in the opposite direction
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What is the frequency of blue light that has a wavelength of 446 nm?
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When I went through with the math, the answer I came upon was: 
<span>6.67 X 10^14 </span>

<span>Here is how I did it: First of all we need to know the equation. </span>

<span>c=nu X lamda </span>
<span>(speed of light) = (frequency)(wavelength) </span>
<span>(3.0 X 10^8 m/s) = (frequency)(450nm) </span>

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<span>Divide the speed of light by the wavelength. </span>
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A charge of 7.2 × 10-5 C is placed in an electric field with a strength of 4.8 × 105 StartFraction N over C EndFraction. If the
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Answer:

2.2 meters

Explanation:

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KE=\frac{kQq}{r}\     \ \ \ \ \ \ ...i

k is Coulomb's constant.

#The electric field,E at radius r is expressed as:

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From i and ii, we have:

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Hence, the distance between the charge and the source of the electric field is 2.2 meters

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