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3 years ago

12

The coefficient of static friction between waxed skis and now snow is 0.14. What force will be needed to get a 700 N skier at re

st moving?
A: 28 N
B: 70 N
C: 98 N
D: 980 N

2 answers:

TiliK225 [7]3 years ago

8 0

Answer:

C. 98 N

Explanation:

The force needed to get the skier at rest moving must be at least equal to the maximum static frictional force acting on the skier, which is given by

$F=\mu W$

where

$\mu = 0.14$ is the coefficient of static friction

W = 700 N is the weight of the skier

Substituting into the equation, we find

$F=(0.14)(700 N)=98 N$

balu736 [363]3 years ago

3 0

Answer:

c

Explanation:

μ = f/N where μ is the coefficient of friction; f is the amount of force that resists motion, and N is the normal force. You must solve for f here so 700 N x .14 = 98 N.

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