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borishaifa [10]

4 years ago

5

Which technological advance allows scientists to handle these objects enough to feel their properties while still protecting the

ir hands?

1 answer:

muminat4 years ago

5 0

The answer depends heavily on what 'objects' you're talking about.

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A 100-kg block being released from rest from a height of 1.0 m. It then takes it 1.40 s to reach the floor. What is the mass m o

dimulka [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass of the other block is $m_1 = 81.14 \ kg$

Explanation:

From the question we are told that

Mass of the first block is $m_1 = 100 \ kg$

The height is $s = 1.0 \ m$

The time it takes it is $t = 1.40 \ s$

Generally from kinematic equation

$s = ut + \frac{1}{2} at^2$

Here u is the initial velocity which zero given that it was at rest initially

So

$s = 0 * t + \frac{1}{2} at^2$

=> $s = \frac{1}{2} at^2$

=> $1 = \frac{1}{2}* a * (1.40 )^2$

=> $a = 1.0204 \ m/s^2$

Generally from the diagram the resultant force due to the weight of the first object and the tension on the string is mathematically represented as

$mg - T = ma$

=> $T = m g - ma$

=> $T = m(g - a)$

=> $T = 877.96 \ N$

Generally from the diagram the resultant force due to the weight of the second object and the tension on the string is mathematically represented as

$T - m_1g = m_1 a$

=> $877.96 = m_1 (a + g)$

=> $877.96 = m_1 (1.0204 + 9.8 )$

=> $m_1 = 81.14 \ kg$

5 0

3 years ago

Which of the following are examples of chemical energy being released or stored?

damaskus [11]

I is the right answer if

3 0

3 years ago

Read 2 more answers

Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa

WINSTONCH [101]

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

$y=0.455m$

And the distance between screen abnd grating is,

$L=1.62 m$

Now the angle can be find as,

$tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62}) \\\theta=15.68^{\circ}$

Now the grating distance is,

$d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m$

Now with m=1 condition will become,

$\lambda=dsin\theta$

So,

$\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm$

Therefore the wavelength of laser light is 491.4 nm.

3 0

3 years ago

A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc

marin [14]

Answer:

Time period of the osculation will be 0.0671 sec

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So $kx=mg$

$k\times 0.04=0.012\times 9.8$

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

$T=2\pi \sqrt{\frac{m}{k}}$

$=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec$

4 0

3 years ago

Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air? The softball expe

scZoUnD [109]

The force of the throw is an applied force

moving through the air is drag

and the downward pull would be due to gravity

7 0

3 years ago

Read 2 more answers