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4 years ago

Que aceleración imprimira una fuerza de 40N aún objeto de 20 kgm de masa

Physics

1 answer:

ale4655 [162]4 years ago

6 0

Answer:

a = 2[m/s^2]

Explanation:

Planteamos la segunda ley de newton del movimiento:

Σ F = m *a

Donde:

m = masa del objeto [kg]

a = aceleracion del objeto [m/s^2]

F = fuerzas que actuan sobre el cuerpo [N]

Reemplazando tenemos:

$a=\frac{40}{20} \\a=2[m/s^2]$

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3 years ago

Car A m= 2000kg<br> v=20 km/h <br> Car B m= 2000kg <br> v= 20km/h what is the location after impact

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Mass of car, M=2000kg

Velocity, V=72× 5/18 =20ms¹

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3 years ago

A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be co

Naddika [18.5K]

Answer:

a = 45 m/s/s

Explanation:

As we know that total mass of the rocket is

$M = 6000 kg$

total mass of the fuel is given as

$m = 2000 kg$

all the fuel is burnt in 15 s

so rate of the fuel burning is given as

$\frac{dm}{dt} = \frac{2000}{15}$

$\frac{dm}{dt} = 133.33 kg/s$

now the thrust force on the rocket is given as

$F_{th} = v\frac{dm}{dt}$

$(6000 - 133.33 t) a = (900 + v)(133.33)$

so we have

$\frac{dv}{900 + v} = (133.33)\frac{dt}{6000 - 133.33 t}$

so we have

$ln(\frac{900 + v}{900}) = - ln(\frac{6000 - 133.3 t}{6000})$

$1 + \frac{v}{900} = \frac{6000}{6000 - 133.3 t}$

now acceleration is rate of change in velocity

$\frac{1}{900}\frac{dv}{dt} = \frac{133.3\times 6000}{(6000 - 133.3t)^2}$

so acceleration at t = 15 s

$a = 45 m/s^2$

3 0

4 years ago