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Lunna [17]
3 years ago
5

Que aceleración imprimira una fuerza de 40N aún objeto de 20 kgm de masa

Physics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

a = 2[m/s^2]

Explanation:

Planteamos la segunda ley de newton del movimiento:

Σ F = m *a

Donde:

m = masa del objeto [kg]

a = aceleracion del objeto [m/s^2]

F = fuerzas que actuan sobre el cuerpo [N]

Reemplazando tenemos:

a=\frac{40}{20} \\a=2[m/s^2]

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1) The energy held in the molecules that your lunch is composed of
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Chemical energy

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The shortening of a transmitted signal's wavelength and/or an increase in its frequency, which indicates that the object is
Mrrafil [7]

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More specifically, the relationship between the apparent frequency, f', and the original frequency, f, is given by:

where:

is the velocity of the wave

is the velocity of the observer relative to the source, and it is positive if the observer is moving towards the source, and negative if the observer is moving away from the source

is the velocity of the source relative to the observer, and it is positive if the source is moving away from the observer, and negative if the source is moving towards the observer

The doppler effect occurs in many daily-life situations: for instance, when an ambulance approaches you, you hear an increase in the apparent frequency of the siren due to the Doppler effect. Another example is the movements of distant galaxies from us: when they move away from us, the apparent frequency of the light they emit decreases, so their wavelengths appear to increase towards the red color (red-shift); on the contrary, when they are moving towards us, the apparent frequency seems to increase, so the wavelength seems to decrease towards the blue color (blue-shift).

Explanation:

7 0
3 years ago
1. A car accelerates uniformly from 12 m/s to 39 m/s in 12 seconds. What is the car's average acceleration
Alinara [238K]

Answer:

(1) 2.25m/s^2

(2) 45.6m

Explanation:

(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds

Therefore the average acceleration can be calculated as follows

a = 39-12/12

a = 27/12

a= 2.25m/s^2

(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds

u= 4

a= 1.2

t= 6

Therefore the distance can be calculated as follows

S= ut + 1/2at^2

= 4×6 + 1/2 × 1.2 × 6^2

= 24 + 1/2 × 1.2 × 36

= 24 + 1/2 × 43.2

= 24 + 21.6

S = 45.6m

Hence the butterfly travels at 45.6m

5 0
2 years ago
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