Answer:
pH of acetic acid solution is 2.88
Explanation:

or, 
or, 
We have to construct an ICE table to determine concentration of
and corresponding pH. Initial concentration of acetic acid is 0.1 M.

I(M): 0.1 0 0
C(M): -x +x +x
E(M): 0.1-x x x
So, ![\frac{[CH_{3}COO^{-}][H^{+}]}{[CH_{3}COOH]}=K_{a}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D%3DK_%7Ba%7D)
or, 
or, 
So,
(M)
so, 
Hence ![pH=-log[H^{+}]=-log(1.33\times 10^{-3})=2.88](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%7B%2B%7D%5D%3D-log%281.33%5Ctimes%2010%5E%7B-3%7D%29%3D2.88)
The second on or the third one
Answer:
93.5 moles N₂
Explanation:
To find the moles, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = number of moles
-----> R = constant (0.0821 atm*L/mol*K)
-----> T = temperature (K)
You can plug the given values into the equation and simplify to find moles. The final answer should have 3 sig figs to match the lowest number of sig figs among the given values.
P = 95.0 atm R = 0.0821 atm*L/mol*K
V = 224 L T = 2773 K
n = ?
PV = nRT
(95.0 atm)(224 L) = n(0.0821 atm*L/mol*K)(2773 K)
21280 = n(227.6633)
93.5 = n
Answer:
Eubacteria
Explanation:
The two prokaryotic kingdoms are Eubacteria and Archaea. A prokaryote is a relatively simple single-celled organism;