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3 years ago

Name on contact force and one field force acting on you right now

Physics

1 answer:

kati45 [8]3 years ago

8 0

Answer:

Contact forces are forces that require the actual contact (touching) of two pieces of matter. There are a variety of contact forces. A very common one is friction. Anytime that two surfaces are in contact with one another, there is friction between the two surfaces. A field force is a force that works at a distance. No touching is required. Gravity is a good example of a field force, because it works whether or not an object is touching something or touching nothing at all.

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The photometer is a device that converts light to voltage which is read out by the digital multimeter (DMM). This is due to the

dimaraw [331]

Answer:

It converts light into electric current.

Explanation:

The first line of the description says that the photometer is a device that converts light to voltage. if the voltage can be measured then current flowing through it can be calculated by Ohms law V=IR.

<em>Hence the photometer converts light to electric current.</em>

The photometer is used to measure the strength of electromagnetic radiation falling on it and operate within the range of ultraviolet ,visible and infrared spectrum.

It converts light to electric current using photodiode (pn junction),photoresistor and photmultiplier.

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3 years ago

The magnetic flux through each turn of a 110-turn coil is given by ΦB = 9.75 ✕ 10−3 sin(ωt), where ω is the angular speed of the

Xelga [282]

Answer:

Explanation:

Given that a coil has a turns of

N = 110 turns

And the flux is given as function of t

ΦB = 9.75 ✕ 10^-3 sin(ωt),

Given that, at an instant the angular velocity is 8.70 ✕ 10² rev/min

ω = 8.70 ✕ 10² rev/min

Converting this to rad/sec

1 rev = 2πrad

Then,

ω = 8.7 × 10² × 2π / 60

ω = 91.11 rad/s

Now, we want to find the induced EMF as a function of time

EMF is given as

ε = —NdΦB/dt

ΦB = 9.75 ✕ 10^-3 sin(ωt),

dΦB/dt = 9.75 × 10^-3•ω Cos(ωt)

So,

ε = —NdΦB/dt

ε = —110 × 9.75 × 10^-3•ω Cos(ωt)

Since ω = 91.11 rad/s

ε = —110 × 9.75 × 10^-3 ×91.11 Cos(91.11t)

ε = —97.71 Cos(91.11t)

The EMF as a function of time is

ε = —97.71 Cos(91.11t)

Extra

The maximum EMF will be when Cos(91.11t) = -1

Then, maximum emf = 97.71V

8 0

3 years ago

Niobium metal becomes a superconductor (with zero electrical resistance) when cooled below 5.1 K. The permeabilty of free space

katovenus [111]

Answer:

687.5 A

Explanation:

We are given that

$\mu_0=1.25664\times 10^{-6}N/A^2$

Magnetic field,B=0.11 T

Diameter,d=2.5mm

Radius,r= $\frac{d}{2}=\frac{2.5}{2}mm=1.25\times 10^{-3} m$

$1mm=10^{-3} m$

We know that current in coil

$I=\frac{2\pi rB}{\mu_0}$

Substitute the values

$I=\frac{2\pi\times 1.25\times 10^{-3}\times 0.11}{1.25664\times 10^{-6}}$

$I=687.5 A$

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3 years ago

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zmey [24]

Answer:

Depends

Explanation:

This depends on the amount of work the energy requires

6 0

4 years ago

What is da answer please i need help

jolli1 [7]

Answer:

Air and water i think

Explanation:

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3 years ago