All categories

2 years ago

Can someone give me 4 examples of comparing stars life cycle to mans life cycle

Physics

1 answer:

dexar [7]2 years ago

3 0

Answer:

After formation, a star uses its fuel and burns brightly; however, upon the consumption of all of its fuel, the star is unable to maintain itself, just as the human body is. This causes the star to either collapse in on itself or burn out completely. Similarly, the life cycle of a human reaches its peak phase after a certain period of maturity and then becomes unable to maintain itself and deteriorates.

Explanation:

You might be interested in

Which statement is most likely correct?

Len [333]

it's either the first or second choice

6 0

3 years ago

Read 2 more answers

14. When incoming light rays strike a flat, plane mirror at an

Mariulka [41]

Answer:

close to the mirrors surface

Explanation:

this is because angle of incidence equals angle of reflection

3 0

2 years ago

What happens to the temperature of a gas when it is compressed? a the temperature does not change. b the temperature increases.

nasty-shy [4]

I think the temperature increases

5 0

3 years ago

Read 2 more answers

Distinguishing between Speed and Velocity.

koban [17]

Answer:

Speed: Distance per time, 400 km/h, and a scalar quantity.

Velocity: Displacement per time, 20 m/s south, and a vector quantity.

Explanation:

Hope this helps! Please mark as brainliest.

Thanks!

8 0

2 years ago

Certain neutron stars (extremely dense stars) are believed to be rotating at about 10 rev/s. If such a star has a radius of 18 k

Aleks [24]

Answer:

mass of the neutron star =3.45185×10^26 Kg

Explanation:

When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.

That is

$\frac{GM_{ns}}{R^2}= \omega^2 R$

M_ns = mass odf the netron star.

G= gravitational constant = 6.67×10^{-11}

R= radius of the star = 18×10^3 m

ω = 10 rev/sec = 20π rads/sec

therefore,

$M_{ns}= \frac{\omega^2R^3}{G} = \frac{4\pi^2\times(18\times10^3)^3}{6.67\times10^{-11}}$

= 3.45185... E26 Kg

= 3.45185×10^26 Kg

4 0

2 years ago