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trasher [3.6K]
3 years ago
5

How can you prevent static sparks while filling your boat's fuel tank?

Physics
2 answers:
kondor19780726 [428]3 years ago
5 0

Answer:

Not to have any contact between fuel pump and tank.

Explanation:

Static spark occurs when there is a imbalance of electric charges at surface of any material. This can even  result into high damage especially while filling boat tank, hence measures should be taken to prevent static sparks.

* Make sure not to have any contact between the brim or surface of fuel pump and the tank's opening.

* Fill the tank carefully without spilling the fuel in water.

* Never fill the tank up to its maximum capacity.

dangina [55]3 years ago
4 0
To prevent static sparks that could occur while you fill fuel is that, a person who is filling the tank should remember that the nozzle of the fuel pump hose should always be in connected or in contact to the tank. This will prevent static sparks from happening to the boat that is going to be used and prevent harm to the person using or refilling the fuel.
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If a mass of .343 kg moves down a 5m ramp in 5.8 seconds, what is the velocity and KE developed by the moving mass
Soloha48 [4]

Velocity 0.86m/s

0.13J

Explanation:

Given parameters:

Mass = 0.343kg

distance = 5m

time taken = 5.8s

Unknown:

Velocity of mass = ?

Kinetic energy = ?

Solution:

Velocity is the rate of change of displacement with time. It is a vector quantity that shows magnitude and direction.

 Mathematically;

   Velocity = \frac{displacement}{time}

  Velocity  = \frac{5}{5.8 } = 0.86m/s

Kinetic energy is the energy due to the motion of a body. It is expressed mathematically as:

  Kinetic energy  = \frac{1}{2}  m v^{2}

m is the mass

v is the velocity

  Kinetic energy  = \frac{1}{2 }   x    0.343  x    0.86^{2} = 0.13J

learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

7 0
4 years ago
Init.
nikklg [1K]

Answer:

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015×10−34 when expressed in the unit J⋅s, which is equal to kg⋅m2⋅s−1, where the metre and the second are defined in terms of c and ΔνCs.

8 0
3 years ago
Read 2 more answers
Two steamrollers begin 100 m apart and head toward each other, each at a constant speed of 1.00 m/s . At the same instant, a fly
Debora [2.8K]

Answer:

The fly travels 2.4 m

Explanation:

Since the Two steamrollers begin 100 m apart and head toward each other, each at a constant speed of 1.00 m/s, we can find the time until they crash by the formula:

Distance = Speed × Time

Time = Distance /Speed

Time = (100 m) / (1 m/s)

Time = 100 hours

Now, the fly will spend the same amount of time traveling as the steamrollers.

Since the fly moves at a speed of 2.4 m/s and we have a time of one hour the steamroller take to collide, then the fly will go a distance of;

Distance = speed x time = 2.4 × 1 = 2.4 m

4 0
3 years ago
A small block on a frictionless, horizontal surface has a mass of 0.0250 kg. It is attached to a massless cord passing through a
frosja888 [35]

Answer:

a) Yes

b) 7 rad/s

c) 0.01034 J

Explanation:

a)

Yes the angular momentum of the block is conserved since the net torque on the block is zero.

b)

m = mass of the block = 0.0250 kg

w₀ = initial angular speed before puling the cord = 1.75 rad/s

r₀ = initial radius before puling the cord = 0.3 m

w = final angular speed after puling the cord = ?

r = final  radius after puling the cord = 0.15 m

Using conservation of angular momentum

m r₀² w₀ = m r² w

r₀² w₀ = r² w

(0.3)² (1.75) = (0.15)² w

w = 7 rad/s

c)

Change in kinetic energy is given as

ΔKE = (0.5) (m r² w² - m r₀² w₀²)

ΔKE = (0.5) ((0.025) (0.15)² (7)² - (0.025) (0.3)² (1.75)²)

ΔKE = 0.01034 J

6 0
3 years ago
A stone sphere of radius 7.00 m rests in a flat field. Relative to the ground, what is the gravitational potential energy of a 9
Molodets [167]

Answer:

(B)  1.23 x 10⁴ J

Explanation:

Given;

radius of the sphere, r = 7.0 m

diameter of the sphere, d = 2r = 14.0 m

mass of the person sitting on the sphere, m = 90.0 kg

The gravitational potential energy of the person is given by;

P.E = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

h is the height above the ground level = d = 14.0 m

P.E = mgh

P.E = (90)(9.8)(14)

P.E = 12348 J

P.E = 1.2348 x 10⁴ J

Therefore, the gravitational potential energy of the person is 1.2348 x 10⁴ J

8 0
3 years ago
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