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lys-0071 [83]
3 years ago
13

Use the "Force applied" slider to set the force applied on the elephant to somewhere in the middle of the range. After you have

set the "Force applied" slider, do not change it again for this question. How would the acceleration change if the mass of the elephant were increased?
Physics
1 answer:
sergeinik [125]3 years ago
8 0

Answer:

the acceleration decrease

Explanation:

Newton's second law states that force is proportional to mass and acceleration

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass

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A hot drink in a room is at a temperature of 20 C
IRISSAK [1]

Answer: the drink cooled down to the same temperature as the room it was in.

Explanation: due to the change and temperature of the room, it cause the heat particles to exchange, causing it cool

8 0
3 years ago
Please help don't for get to show work
emmasim [6.3K]
-- Bob covered a distance of (32m + 45m) = 77 meters.

-- His displacement is the straight-line distance and direction
from his starting point to his ending point.

The straight-line distance is

D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters

The direction is the angle whose tangent is (32/45) south of east.

tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
3 0
3 years ago
A +5.0 uC point charge is placed at the 0 cm mark of a meter stick and a -4.0 °C charge is
viva [34]

Answer:

-1.44*10^11v/m

Explanation:

6 0
3 years ago
A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0
Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

<u>t = 7.5 s</u>

6 0
3 years ago
Why do scientists use two different models of light​
mrs_skeptik [129]

Answer:

To distinguish results based on the only two variables of

awareness.

Explanation:

5 0
3 years ago
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