Cell membrane can also be called plasma membrane
In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. It is expressed as </span><span>Work done = force (N) X distance (m). From the problem statement, the distance traveled is zero. Therefore, the work done is zero as well.</span>
Answer:
37.5 N Hard
Explanation:
Hook's law: The force applied to an elastic material is directly proportional to the extension provided the elastic limit of the material is not exceeded.
Using the expression for hook's law,
F = ke.............. Equation 1
F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.
Given: k = 750 N/m, e = 5.0 cm = 0.05 m
Substitute into equation 1
F = 750(0.05)
F = 37.5 N
Hence the athlete is pushing 37.5 N hard
The change in surface area of Gaussian surface with radius (r) is 8πr.
<h3>
Electric field from Coulomb's law</h3>
The electric field experienced by a charge is calculated as follows;

where;
- E is the electric field
- Q is the charge
- r is the radius
The electric field reduces by a factor of 
<h3>Surface area of a Gaussian surface;</h3>
The surface area of a sphere is given as;

<h3>Change in area with r</h3>

Thus, the change in surface area of Gaussian surface with radius (r) is 8πr.
Learn more about area of Gaussian surfaces here: brainly.com/question/17060446
Answer:
A)0.00022s b)40363.6N c) 0.025m/s
Explanation:
Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m
Initial speed of the bullet = 1300m/s, final speed = 930m/s
Using equation of motion
Distance = 1/2(vf+vi)*t (time in seconds)
t = 0.25*2/(1300+930) = 0.00022s
B) force exerted on the body
F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022
F = -40363N, it is negative because the body decelerated during this motion
C) using law of conservation of momentum,
M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2
The target was at rest so initial speed U2 = 0
0.024*1300 + 360*0 = 0.024*930 + 360*V2
31.2 = 22.32+360*V2
31.2-22.33 = 360*V2
V2 = 8.88/360 = 0.025m/s