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Verizon [17]
3 years ago
5

How many air molecules are in a 13.0×12.0×10.0 ft room (28.2 L=1 ft3)? Assume atmospheric pressure of 1.00 atm, a room temperatu

re of 20.0 ∘C, and ideal behavior.
Physics
1 answer:
aksik [14]3 years ago
4 0

Answer:

1963.93 Moles

Explanation:

-We know the standard conversion ratio for the volume of a mole is 1 Mole=22.4L

Given volume of rooms as 13.0ft\times12.0ft\times10ft=1560 ft^3

Convert the volume into liters:1560\times28.2l=43992l

#From our conversion ratio above, we get the volume of air molecules in moles as:

V_m=\frac{43992L}{22.4L}\times 1\ mole\\\\=1963.93\ Moles

Hence, the volume of air molecules is 1963.93 Moles

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Light energy with very high amplitude would be perceived as ________.
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Answer:

High amplitude is equivalent to loud sounds.

Explanation:

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If the kinetic and potential energy in a system are equal, then the potential energy increases. What happens as a resul
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-- If the system is 'closed', then nothing ... including energy ... can get in or out, and the total energy inside has to be constant.

If half of the energy in the system starts out as potential energy and the rest starts out as kinetic, and then the potential energy increases, there's only one place the increase could have come from ... it could only have been converted from kinetic energy.  So the <em>kinetic energy</em> in the system <em>must</em> <em>decrease</em>.

In fact, this isn't even a "result".  The kinetic energy has to decrease <em><u>before</u></em> the potential energy can increase, because that's where the increase has to come from.

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3 years ago
A power plant produces 1000 MW to supply a city 40 km away. Current flows from the power plant on a single wire of resistance 0.
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Answer:

Current = 8696 A

Fraction of power lost = \dfrac{80}{529} = 0.151

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Electric power is given by

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Using values from the question,

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The power loss is given by

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R = 0.050\times40 = 2\Omega

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P_\text{loss} = \left(\dfrac{200000}{23}\right)^2\times2

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I belive what your looking for is oxygen

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