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lorasvet [3.4K]
3 years ago
11

Needed substance are carried to the body cells by ehat

Physics
1 answer:
agasfer [191]3 years ago
3 0
Oh my gosh had the same question
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Small blocks A and B are held at rest on a smooth plane inclined at 30° to the horizontal. Each is held in equilibrium by a forc
Olin [163]
<h3><u>Answer</u> :</h3>

First of all, See the attachment for better understanding.

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

❂ <u>Weight of block A</u> :

➝ mg sin30° = 18

➝ W (1/2) = 18

➝ W = 18×2

➝ <u>W = 36N </u>

❂ <u>Weight of block B</u> :

➝ N sin30° = 18

➝ (Mg cos30°) sin30° = 18

➝ W' (√3/2)(1/2) = 18

➝ W' (√3/4) = 18

➝ W' = 72/√3

➝ <u>W' = 41.61N</u>

5 0
3 years ago
A real (non-Carnot) heat engine, operating between heat reservoirs at temperatures of and performs 4.1 kJ of net work, and rejec
Sati [7]
There are some missing data in the problem. The full text is the following:
"<span>A </span>real<span> (</span>non-Carnot<span>) </span>heat engine<span>, </span>operating between heat reservoirs<span> at </span>temperatures<span> of 710 K and 270 K </span>performs 4.1 kJ<span> of </span>net work<span>, and </span>rejects<span> 9.7 </span>kJ<span> of </span>heat<span>, in a </span>single cycle<span>. The </span>thermal efficiency<span> of a </span>Carnot heat<span> engine, operating between the same </span>heat<span> reservoirs, in percent, is closest to.."

Solution:
The efficiency of a Carnot cycle working between cold temperature </span>T_C and  hot temperature T_H is given by
\eta = 1 - \frac{T_C}{T_H}
and it represents the maximum efficiency that can be reached by a machine operating between these temperatures. If we use the temperatures of the problem, T_C=270 K and T_H=710 K, the efficiency is
\eta = 1 - \frac{270 K}{710 K}=0.62 = 62%

Therefore, the correct answer is D) 62 %.
6 0
4 years ago
If we compare and contrast electromagnetic waves with sound waves, all BUT one statement is true. That is A) sound waves require
ehidna [41]

its c electromagnetic waves must have a medium in which to travel, but sound waves can travel anywhere.

6 0
3 years ago
Read 2 more answers
Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml
Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of  electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}

Put the value into the formula

E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}

E=2.41\times10^{3}\ V/m

Hence, The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

3 0
4 years ago
A 1,198 N sky diver has opened his parachute to slow his descent to a constant speed the parachute applies 1,277 N of force. He
Savatey [412]

The mass of the skydiver is 122.2 kg

Explanation:

We can solve the problem by using the concept of weight.

The weight of a body is the force of gravity acting on the body; near the Earth's surface, its magnitude is given by

W=mg

where

m is the mass of the body

g=9.8 m/s^2 is the acceleration of gravity

In this problem, we know the weight of the skydiver:

W = 1198 N

So we can re-arrange the equation to find its mass:

m=\frac{W}{g}=\frac{1198}{9.8}=122.2 kg

Learn more about weight here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

6 0
4 years ago
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