Let's assume time taken by plane on one way distance as 't'
The total flying time in both directions was 10.5 hr
so, time taken in other direction =10.5-t
now, we are given
A plane averaged 500 mph on a trip going east
so, total distance of one way is
total distance of other way is
now, we can that distance is same from both sides
so, we get
now, we can solve for t
now, we can find one way distance
miles..............Answer
Answer:
Answer: 119.32
Step-by-step explanation:
To find circumference you must do diameter × pi or radius × 2 × pi sense we are given the diameter its easy peasy so we can just do 38 × pi so... 38 × 3.14 = 119.32 so 119.32 is the cirmcumfrence Hope that helps!!
A: Suppose Mr. Moore decides to use 20 seventh graders as the sample. Is this sample a random sample? Explain your reasoning.
Ans: No, because he only chose the seventh graders which is invalid since he wants to have to use the mean height which involves the 6th, 7th and 8th graders.
B: Mr. Moore decides to use a random number generator to select 20 students from the school. Suppose that when choosing 20 students using the random generator on the graphing calculator, Mr. Moore’s sample is all eighth graders. Does that mean the sample is not a random sample? Explain your reasoning.
Ans: No, it is still a random sample. Since he is using a random generator, there is a possibility that the random generator would pick all students from the 8th grade. Unlike the first one, the random generator is not biased towards any grade, it is just a coincidence.
Answer:
r = 13, 3
Step-by-step explanation:
| r - 8| = 5
All solutions for r by breaking the absolute value into the positive and negative components
r = 13, 3
Option B is correct.
Step-by-step explanation:
We need to solve: ![\sqrt[3]{x^2}\sqrt[4]{x^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D)
We know that: ![\sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Csqrt%5Bb%5D%7Bx%7D%20%3D%5Csqrt%5Bn%2Ab%5D%7Bx.x%7D%3D%20%5Csqrt%5Bn%2Ab%5D%7Bx%5E2%7D)
Applying the above rule:
![\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%5Csqrt%5B4%5D%7Bx%5E3%7D%5C%5C%3D%5Csqrt%5B3%2A4%5D%7Bx%5E2.x%5E3%7D%5C%5C%3D%5Csqrt%5B12%5D%7Bx%5E5%7D)
So, Option B is correct.
Keywords: Solving with Exponents
Learn more about Solving with Exponents at:
#learnwithBrainly
