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gizmo_the_mogwai [7]
3 years ago
6

Consider the rational number, −0.4. Is the number greater than −2 and 1/3 but less than 4/5 ?

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:

No

Step-by-step explanation:

Since the rational number -0.4 is a negative, it cannot have a greater value than 1/3 since it is a positive.

Though, the rest of the sentence is true.

-0.4 > -2

-0.4 < 4/5

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Natali [406]
I believe it is neither

For one if you plug in either of them the first one is going to be negative 3. But if you use the second one then your answer would be -3+12= -10 but -3+12 is 9 so I would go with neither because I don't see how it's both
4 0
3 years ago
Which two steps could be taken to simplify the expression y/3 + 2 = 11?<br>​
IRINA_888 [86]

Answer:

y = 27

Step-by-step explanation:

y/3 + 2 = 11

First subtract 2 from each side

y/3 + 2-2 = 11-2

y/3  = 9

Then multiply each side by 3

y/3 *3 = 9*3

y = 27

8 0
3 years ago
Read 2 more answers
Need help with this question plz!!
mel-nik [20]

Let us consider the image on the left that is the image in which 1 and 2 , 3 and 4 are connected as image 1 and the other as image 2.

1. All Vertices are connected by the least amount of edges. True

2. Vertex 1 and 2 are not connected. This is false for image

1 and true for image 2

3.  Vertex 3 and 4 are not connected. This is false for image

1 and true for image 2

4. You can get to Vertex 1 from Vertex 4 by going through Vertex 3. This is true for image 1

5 0
3 years ago
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One teacher wants to give each students 5/9of a slice of pizza. If the teacher has 15 slices of pizza,then how many students wil
valentina_108 [34]

Answer:

Step-by-step explanation:

10

5 0
3 years ago
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The tables represent two linear functions in a system,
Alenkasestr [34]

Answer:

<h2>(8, -22)</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

First table:

(-4, 26), (0, 10) → b = 10

m=\dfrac{10-26}{0-(-4)}=\dfrac{-16}{4}=-4

\boxed{y=-4x+10}

Second table:

(-4, 14), (0, 2) → b = 2

m=\dfrac{2-14}{0-(-4)}=\dfrac{-12}{4}=-3

\boxed{y=-3x+2}

We have the system of equations:

\left\{\begin{array}{ccc}y=-4x+10&(1)\\y=-3x+2&(2)\end{array}\right\\\\\text{Put (1) to (2):}\\\\-4x+10=-3x+2\qquad\text{subtract 10 from both sides}\\-4x=-3x-8\qquad\text{add 3x to both sides}\\-x=-8\qquad\text{change the signs}\\x=8\\\\\text{Put the value of x to (2):}\\\\y=-3(8)+2\\y=-24+2\\y=-22

5 0
3 years ago
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