Answer:
C
Step-by-step explanation:
First of all their is an easier way solving this 2l/ + l^2
but how you need it is c because the base is 100 and each face is 40 how 10x8=80 80/2=40
Simplify the following:
((x^2 - 11 x + 30) (x^2 + 6 x + 5))/((x^2 - 25) (x - 5 x - 6))
The factors of 5 that sum to 6 are 5 and 1. So, x^2 + 6 x + 5 = (x + 5) (x + 1):
((x + 5) (x + 1) (x^2 - 11 x + 30))/((x^2 - 25) (x - 5 x - 6))
The factors of 30 that sum to -11 are -5 and -6. So, x^2 - 11 x + 30 = (x - 5) (x - 6):
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (x - 5 x - 6))
x - 5 x = -4 x:
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (-4 x - 6))
Factor -2 out of -4 x - 6:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (2 x + 3) (x^2 - 25))
x^2 - 25 = x^2 - 5^2:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (x^2 - 5^2) (2 x + 3))
Factor the difference of two squares. x^2 - 5^2 = (x - 5) (x + 5):
((x - 5) (x - 6) (x + 5) (x + 1))/(-2(x - 5) (x + 5) (2 x + 3))
((x - 5) (x - 6) (x + 5) (x + 1))/((x - 5) (x + 5) (-2) (2 x + 3)) = ((x - 5) (x + 5))/((x - 5) (x + 5))×((x - 6) (x + 1))/(-2 (2 x + 3)) = ((x - 6) (x + 1))/(-2 (2 x + 3)):
((x - 6) (x + 1))/(-2 (2 x + 3))
Multiply numerator and denominator of ((x - 6) (x + 1))/(-2 (2 x + 3)) by -1:
Answer: (-(x - 6) (x + 1))/(2 (2 x + 3))
The graph that best represent the relationship between time and cost is option A as it is a proportional graph
<h3>How to know the graph that represent the relationship between time and number of team?</h3>
Each week 6 teams register to participate.
Therefore, for every week 6 team register to participate in the competition.
This simply implies as time increases , the number of participant in the competition also increase.
Therefore, the equation that can be use to represent this situation is as follows:
y = 6x
where
- y = number of team registered
- x = time in weeks.
Hence, the graph that best represent the relationship between time and cost is option A as it is a proportional graph. The registered team increases as the time in weeks increase.
learn more on graph relationship here: brainly.com/question/12812258
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No it's not_______________
Explanation:
Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.
Assume the quadratic equation to be
where x is the variable.
Completing the square method is as follows:
- send the constant term to other side of equal
![\mathbf{ax^{2}+bx=-c}](https://tex.z-dn.net/?f=%5Cmathbf%7Bax%5E%7B2%7D%2Bbx%3D-c%7D)
- divide the whole equation be coefficient of
, this will give ![\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%5E%7B2%7D%2B%5Cfrac%7Bb%7D%7Ba%7Dx%3D-%20%5Cfrac%7Bc%7D%7Ba%7D%7D)
- add
to both side of equality ![\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%5E%7B2%7D%2B2%5Ctimes%5Cfrac%7Bb%7D%7B2a%7Dx%2B%5Cfrac%7Bb%7D%7B2a%7D%5E%7B2%7D%3D-%5Cfrac%7Bc%7D%7Ba%7D%2B%5Cfrac%7Bb%7D%7B2a%7D%5E%7B2%7D%7D)
- Make one fraction on the right side and compress the expression on the left side
![\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28x%2B%5Cfrac%7Bb%7D%7B2a%7D%29%5E%7B2%7D%3D%5Cfrac%7Bb%5E%7B2%7D-4ac%7D%7B4a%5E%7B2%7D%7D%7D)
- rearrange the terms will give the vertex form of standard quadratic equation
![\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}](https://tex.z-dn.net/?f=%5Cmathbf%7Ba%28x%2B%5Cfrac%7Bb%7D%7B2a%7D%29%5E%7B2%7D-%5Cfrac%7Bb%5E%7B2%7D-4ac%7D%7B4a%7D%3D0%7D)
Follow the above procedure will give the vertex form.
(NOTE : you must know that
. Use this equation in transforming the equation from step 3 to step 4)