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maksim [4K]
3 years ago
13

What are 5 ways to conserve energy at school?

Physics
1 answer:
Gnoma [55]3 years ago
5 0
1. turn off lights in classrooms when not in use.
2. turn off all computers when not in use.
3.use a small amount of water when washing your hands.
4. Don't charge your cell phones during class.
5. open windows instead of using air conditioner
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Four solid balls, each with a different mass, are moving at the same speed. Which ball would require the most force to stop its
zhannawk [14.2K]
Obviouly 20kg.............
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The wave property that is related to the height of a wave is the
DedPeter [7]

Answer:

Amplitude

Explanation:

The amplitude is maximum height a wave is measured from its rest position.

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4 years ago
How to find the frictional force acting on an object (not the friction coefficient)? ...?
Dovator [93]
One can simply find the frictional force acting on an object using this equation:

 (Ffrict<span> = μ•F</span>norm<span>)
</span>

The process of determining the value of the individual forces acting upon an object involve an application of Newton's second law (Fnet=m•a) and an application of the meaning of the net force. If mass (m) and acceleration (a) are known, then the net force (Fnet) can be determined by use of the equation.

<span>Fnet = m • a</span>

If the numerical value for the net force and the direction of the net force is known, then the value of all individual forces can be determined.

7 0
3 years ago
what kind of wave would be observed in outer space between planets where there is very little matter?
ddd [48]
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5 0
3 years ago
A heavy piece of hanging sculpture is suspended by a 90 cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at it
kupik [55]

Answer: The mass of the sculpture is 11.8kg

Explanation:

Using the equation of fundamental frequency of a taut string.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where

f= frequency in Hertz =80Hz

T = Tension in the string = Mg

M represent the mass of the substance (sculpture) =?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

μ= mass density = mass of string /Length of string

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

80= 1/(2*0.9) √(T/0.0056)

144= √(T/0.0056)

Square both sides

20736= T/0.0056

T= 116.12N

Recall that T =Mg

116.12= M * 9.8

M=116.12/9.8

M= 11.8kg

Therefore the mass of the sculpture is 11.8kg

4 0
3 years ago
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