Um honestly I have no clue. Maybe you're in a cold room lol.
Answer:
Kinetic energy, E = 9.1 eV
Explanation:
It is given that,
At the first excited state of a particular atom is 5.7 eV above the ground state. The kinetic energy of the atom after the collision is 3.4 eV.
We need to find the kinetic energy of the electron just before the collision. The conservation of momentum will be followed here. The energy gets transferred from moving electrons to these atoms is 5.7.
Let E is the kinetic energy of the electron just before the collision. It is equal to :
E = 5.7 eV + 3.4 eV
E = 9.1 eV
So, the kinetic energy of the electron just before the collision is 9.1 eV. Hence, this is the required solution.
I beleive that the wave with higher frequency will have shorter wavelength
Explanation:
First find the displacement in the x direction:
dₓ = 449 cos 66° + 1112 cos 169° + 1571 cos 26°
dₓ = 182.6 − 1091.6 + 1412
dₓ = 503 km
Next, find the displacement in the y direction:
dᵧ = 449 sin 66° + 1112 sin 169° + 1571 sin 26°
dᵧ = 410.2 + 212.2 + 688.7
dᵧ = 1311 km
The magnitude is:
d² = dₓ² + dᵧ²
d² = (503)² + (1311)²
d = 1404 km
The angle is:
tan θ = dᵧ / dₓ
tan θ = 1311 / 503
tan θ = 2.61
θ = 69°
1404 km and 69° north of east from New Orleans is approximately Toledo.
Answer:

Explanation:
The difference of pressure is given by gauge pressure:


