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Alina [70]
3 years ago
6

A machine has an efficiency of 80%. How much work must be done on the machine so to make it do 50,000 J of output work?

Physics
2 answers:
Tamiku [17]3 years ago
8 0

Work formula is Work=N∙M or Joule (J)

So you have the following given:

50 000 is the output work

.8 is the efficiency

 if you input the given = 50000 = .8*J

To get the answer just divide 50000 by .8 to get the answer.

62,500 J is the amount of work to be done.

gogolik [260]3 years ago
5 0
<h3><u>Answer;</u></h3>

62,500 Joules

<h3><u>Explanation;</u></h3>
  • Efficiency is a measure of how much work or energy is conserved in a process. It can be stated as the percentage of the output work divided by the input work minus the work lost from to friction and heat.

<em>Efficiency = (output work/ input work) × 100%</em>

<em>         80 % = 50,000 / input work  × 100%</em>

<em>              0.8 = 50,000 /input work </em>

<em> Input work = 50,000/0.8 </em>

<em>                   =</em><u><em> 62500 Joules</em></u>

<em>Thus; the work input is </em><u><em>62,500 joules.</em></u>

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