Question

Ask Your Teacher A circular wire loop whose radius is 10.0 cm carries a current of 3.60 A. It is placed so that the normal to its plane makes an angle of 39.0° with a uniform magnetic field of 12.0 T. (a) Calculate the magnetic dipole moment of the loop.

Answer 1

Answer:

$M=0.113\ Am^2$

Explanation:

Given that,

Radius of the circular loop, r = 10 cm = 0.1 m

Current flowing in the loop, I = 3.6 A

Uniform magnetic field, B = 12 T

To find,

The magnetic dipole moment of the loop.

Solution,

Let M is the magnitude of magnetic dipole moment of the loop. We know that the product of current flowing and the area of cross section. Its formula is given by :

$M=I\times A$

A is the area of circular wire

$M=I\times \pi r^2$

$M=3.6\ A \times \pi (0.1\ m)^2$

$M=0.113\ Am^2$

Therefore, the magnetic dipole moment of the loop is $0.113\ Am^2$. Hence, this is the required solution.