Answer:
Radius = 9.0216 cm
Explanation:
Given that:
The critical mass of neptunium-237 = 60 kg
Also, 1 kg = 1000 g
So mass = 60000 g
Density = 19.5 g/cm³
Volume = ?
So, volume:
The volume of the material = 3076.92308 cm³
The expression for the volume of the sphere is:




![{(radius)}=\sqrt[3]{\frac{64615.38468}{88}}](https://tex.z-dn.net/?f=%7B%28radius%29%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B64615.38468%7D%7B88%7D%7D)
<u>Radius = 9.0216 cm</u>
Answer:
Explanation:
ω = 
k = 2.5 N/m
m = 10 kg

ω = .5 rad /s
x(t) = A cos(ωt + φ₀)
When t = 0 , x(t) = 0
0 = A cos(ωx 0 + φ₀)
cos φ₀ = 0
φ₀ = π /2
x(t) = A cos(ωt +π /2 )
Putting the value of ω
x(t) = A cos(.5 t +π /2 )
Differentiating on both sides
dx(t)/dt = - .5 A sin(.5 t +π /2 )
v(t) = - .5 A sin(.5 t +π /2 )
Given t =0 , v(t) = -5 m/s
-5 = - .5 A sin(.5 x0 +π /2 )
-5 = - .5 A sinπ /2
A = 10 m
x(t) = 10 cos( .5 t +π /2 )
b )
when t = π ( 3.14 s )
x(t) = - 10 m
when t = 2π ( 6.28s )
x(t) = 0
when t = 3π ( 9.42 s )
x(t) = 10 m
and so on
Answer:
1.507×10⁻⁴ T
Explanation:
a = 5 cm = 0.05 m
b = 7 cm = 0.07 m
j = 1 A/cm²
Distance from magnetic field = d = 10 cm = 0.1 m
μ₀ = Vacuum permeability = 4π×10⁻⁷ H/m
Magnetic of hollow cylinder

∴ Magnitude of the magnetic field at a distance d = 10 cm from the axis of the cylinder is 1.507×10⁻⁴ T
4). Frequency
I had a class on it.