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4 years ago

Write the correct formula for the compounds that each of the following pairs of ions will make.

Chemistry

1 answer:

Deffense [45]4 years ago

6 0

Answer: do you go to north too ?

Explanation:

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Whats 2 +5 + 6 + 9 right awnser please

masya89 [10]

Answer:

the awnser is 22

Explanation:

9+6 = 15 + 7 = 22 have a great day

5 0

2 years ago

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Be sure to answer all parts. A 0.365−mol sample of HX is dissolved in enough H2O to form 835.0 mL of solution. If the pH of the

Marta_Voda [28]

Answer:

The Ka is 9.11 *10^-8

Explanation:

Step 1: Data given

Moles of HX = 0.365

Volume of the solution = 835.0 mL = 0.835 L

pH of the solution = 3.70

Step 2: Calculate molarity of HX

Molarity HX = moles HX / volume solution

Molarity HX = 0.365 mol / 0.835 L

Molarity HX = 0.437 M

Step 3: ICE-chart

[H+] = [H3O+] = 10^-3.70 = 1.995 *10^-4

Initial concentration of HX = 0.437 M

Initial concentration of X- and H3O+ = 0M

Since the mole ratio is 1:1; there will react x M

The concentration at the equilibrium is:

[HX] = (0.437 - x)M

[X-] = x M

[H3O+] = 1.995*10^-4 M

Since 0+x = 1.995*10^-4 ⇒ x=1.995*10^-4

[HX] = 0.437 - 1.995*10^-4 ≈ 0.437 M

[X-] = x = 1.995*10^-4 M

Step 4: Calculate Ka

Ka = [X-]*[H3O+] / [HX]

Ka = ((1.995*10^-4)²)/ 0.437

Ka = 9.11 *10^-8

The Ka is 9.11 *10^-8

4 0

3 years ago

A compound is 21.6% Mg, 21.4% C, and 57.0% O. What is the empirical formula of the compound?

nignag [31]

Answer:

Compound x = $MgC_{2}O_{4}$

Explanation:

Let the compound be x

Assuming we have a 100g of compound x

Given the following data;

Magnesium, Mg = 21.6% = 21.6g

Carbon, C = 21.4% = 21.4g

Oxygen, O = 57.0% = 57.0g

Now, we would find the amount of moles for each element.

Atomic mass of Mg = 24.30g

Atomic mass of C = 12.01g

Atomic mass of O = 16.00g

Amount of moles for Mg;

21.6*(1/24.30) = 0.89mol

Amount of moles for C;

21.4*(1/12.01) = 1.78mol

Amount of moles for O;

57.0*(1/16.00) = 3.56mol

We then divide by the smallest to find the ratio;

0.89/0.89 = 1 Mol of Mg

1.78/0.89 = 2 Mol of C

3.56/0.89 = 4 Mol of O

Therefore, the ratio of Mg, C and O is 1:2:4.

Compound x = $MgC_{2}O_{4}$

Hence, the empirical formula of the compound is $MgC_{2}O_{4}$

7 0

3 years ago

Food is cooked faster in pressure cooker. why?

horrorfan [7]

Answer:

Answer below

Explanation:

because the pressure of the pressure cooker compresses it and then it cooks faster

6 0

2 years ago

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How many molecules of ethane ( C2H6) are present in 0.197g of C2H6?

Brut [27]

Answer:

3.945 x 10²¹ molecules

Explanation:

Firstly, we need to calculate the no. of moles using the relation:

n = mass/molar mass = (0.197 g)/(30.07 g/mol) = 6.55 x 10⁻³ mol.

It is known that every 1.0 mol of a molecule contains Avogadro's number of molecules (NA = 6.022 x 10²³).

∴ 0.197 g of C₂H₆ will contain = (6.55 x 10⁻³ mol)(6.022 x 10²³) = 3.945 x 10²¹ molecules.

4 0

3 years ago

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