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Step2247 [10]
3 years ago
8

How is an electrons energy related to its position in an atom?

Chemistry
1 answer:
balu736 [363]3 years ago
6 0

Answer: The amount of energy needed to move an electron from one zone to another is a fixed, finite amount. The electron with its extra packet of energy becomes excited, and promptly moves out of its lower energy level and takes up a position in a higher energy level.

Explanation:

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How many moles are in 454 Liters of a gas?
Natalka [10]

Answer:

20.27 mol

Explanation:

454 L x (1 mol/22.4 L) = 20.27 mol

3 0
3 years ago
Conociendo el volumen de la solución y la masa del soluto y su masa molar, ¿qué concentración es posible determinar
NISA [10]

Answer:

Conociendo el volumen de solución, masa de soluto y su masa molar, es posible determinar: B) Concentración molar

La molaridad es la relación entre el número de moles de soluto y los litros de solución. Más:

M = No moles de solución de soluto / volumen (L)

Y a su vez los moles de soluto se encuentran por:

No moles de soluto = masa soluto / masa molar soluto

8 0
3 years ago
I'm boaaaaaaaaaaaaaaard yall like entertain me lol jkjkj
vazorg [7]

^{hello}.

Sorry, I'm am not going to entertain you!

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#LearnWithBrainly

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7 0
3 years ago
What element do you think is the most abundant in the star that you observed in part two? explain your answer?
mote1985 [20]
The most abundant element in the Sun and in the stars are hydrogen and helium. Like most of the stars, there is a spontaneous radioactive reaction happening in the Sun. Hydrogen is transformed into Helium. As long as the stars are young, the most abundant element is hydrogen.
6 0
3 years ago
Express the concentration of a 0.0610 m aqueous solution of fluoride, f–, in mass percentage and in parts per million. assume th
ASHA 777 [7]
<span>Assume you have 1 L of solution.
Moles F- = M F- x L F- = (0.0610)(1) = 0.0610 moles F-
0.0610 moles F- x(19.0 g F-/1mole F-) = 1.159 g F- in 1 L of solution
1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g of solution
mass % F- = (g F- / g solution) x 100 = (1.159 / 1000) x 100
= 0.1159%
parts per million F- = mg F- /L = 1159 / 1 = 1159 ppm F-</span>
8 0
3 years ago
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