What is the gram-formula mass of Ca3(PO4)2

In this experiment the crest of one wave combined with the crest of the second wave to produce _______________.

timurjin [86]

Answer:

B a large upward displacement

Explanation:

3 0

2 years ago

Read 2 more answers

A 25 liter gas cylinder contains 10 mole of carbon dioxide. Calculate the pressure, in atm, of the gas at 325K.

Arada [10]

<u>Answer:</u> The pressure of carbon dioxide gas is 11 atm

<u>Explanation:</u>

To calculate the pressure of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = pressure of the gas = ?

V = Volume of gas = 25 L

n = number of moles of gas = 10 mole

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = 325 K

Putting values in above equation, we get:

$P\times 25L=10mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 325K\\\\P=11atm$

Hence, the pressure of carbon dioxide gas is 11 atm

4 0

2 years ago

An aqueous solution of 1.29 M ethanol, CH3CH2OH, has a density of 0.988 g/mL. The percent by mass of CH3CH2OH in the solution is

anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

$m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g$

Now, the mass of the ethanol:

$m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g$

Finally, the by mass percent is:

$m/m=\frac{59.34g}{988g}*100\\$ %

%m=6%

Best regards.

4 0

2 years ago

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h b

iragen [17]

$C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O

540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O

\\ \\30 mmolH_{2}O -have - 60 mmol H
\\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H
\\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C
\\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C

20 mmol C: 60 mmol H=1 mol C : 3 mol H

$

7 0

3 years ago

If a dog has a mass of 21.5kg, what is his mass in the following units?

PolarNik [594]

Answer: 21.5kg in grams is 21,500 grams

21.5kg in mg is 215,000,00

Explanation:

5 0

3 years ago