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3 years ago

This freshwater ecosystem is home to rooted plants.

1 answer:

4 0

A. LITTORAL ZONE is a freshwater ecosystem that is home to rooted plants.

Littoral zone is the shallow area of a lake, pond, river or ocean. This is the area where mangroves grow.

Some counties and water district identify littoral zones so that these zone will be planted with native plants. This is done for the purpose of having the plants purify the water and maintain a balanced ecosystems.

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The molar mass of BeBr2 is

valentina_108 [34]

Answer:

168.812 g/mol

Explanation:

atomic mass. of Be= 9.012

atomic mass of Br= 79.90

because there is a 2 after Br you double the atomic mass

79.90(2)= 159.8

To find the molar mass add the atomic masses of each element

9.012+159.8=168.812

3 0

4 years ago

Read 2 more answers

What happens to the amount of carbon dioxide as the population increases?

Roman55 [17]

Answer:

when population increases the amount of carbon dioxide also increases as population use oxygen and release carbon dioxide

5 0

4 years ago

2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the eleme

mixer [17]

Answer:

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

$2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^{2+} + 2H_2O$

Next, we assign the oxidation numbers as follows:

$2N^{2+}O^{2-} + 3Mn^{4+}O^{-2}_2 + 4H^+ \rightarrow 2(N^{5+}O^{2-}_3)^- + 3Mn^{2+} + 2H^+_2O^{2-}$

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

Regards!

4 0

3 years ago

011 10.0 points

Sphinxa [80]

Answer:

$-58.3^{\circ}C$

Explanation:

The frequency and the wavelength of a wave are related by the equation

$v=f\lambda$

where

v is the speed

f is the frequency

$\lambda$ is the wavelength

For the sound wave in this problem, we have

f = 634 Hz (frequency)

$\lambda=0.47 m$ (wavelength)

Therefore, the speed of the wave is

$v=(634)(0.47)=298 m/s$

The speed of sound in air depends on the temperature according to the equation

$v=333+0.6 T$

where T is the temperature.

In this problem, we know the speed, so we can calculate the temperature:

$T=\frac{v-333}{0.6}=\frac{298-333}{0.6}=-58.3^{\circ}C$

7 0

3 years ago

Apply the law of conservation of energy to explain how energy is conserved when water evaporates?

ivanzaharov [21]

Energy and mass have not been created, the water has simply been changed to a different form, but it is still present, and could be condense down into the same form with the same mass.

5 0

3 years ago