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4 years ago

Luis is installing some 12 gage wire. How much resistance will there be throughout a distance of 400 feet

Engineering

2 answers:

VLD [36.1K]4 years ago

5 0

I don't know at this point i'm just hungry for points lol

garri49 [273]4 years ago

4 0

Answer:

0.635 m

Explanation:

When calculating the resistance R of a wire, we need its length(l), its cross-sectional area (A) and the resistivity of the material(ρ). The resistance of a wire is given by the equation:

Resistance (R) = Resistivity(ρ) × length (l) / cross-sectional area (A)

For a 12 guage wire,

Resistivity (ρ) = 1.724 × 10 ⁻⁸ ohm m, length (l) = 400 ft = 121.92 m,

Diameter (d) = 0.00205232, cross-sectional area (A) = πd²/4 = π(0.00205232)²/4 = 3.31 × 10 ⁻⁶ m²

$R=\frac{\rho l}{A}=\frac{1.724*10^{-8}*121.92}{3.31*10^{-6}} =0.635m$

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Answer:

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3 years ago

A 900 kg car is accelerated from a speed of 10 m/s to 30 m/s. An estimated heat loss of 20 BTU's occurs during the acceleration.

Strike441 [17]

Answer:

Work = 651,1011 kJ

Explanation:

Let´s take the car as a system in order to apply the first law of thermodynamics as follows:

$E_{in}- E_{out}=E_{system,final}- E_{system,initial}$

Where

$E_{in}- E_{out}=(Q_{in}-Q_{out})_{heat}+(W_{in}-W_{out})_{work}+(Em_{in}-Em_{out})_{mass}$

And considering that there is no mass transfer and that the only energy flows that interact with the system are the heat losses and the work needed to move the car we have:

$E_{in}- E_{out}=-Q_{out}+W_{in}$

Regarding the energy system we have the following:

$E_{system,final}- E_{system,initial}=(U_{f}-U_{i})_{internal}+(1/2m(V^2_{f}-V^2_{i}))_{kinetic}+(mg(h_{f}-h_{i}))_{potential}$

By doing the calculations we have:

$E_{system,final}- E_{system,initial}=[0,1*900]_{internal}+[0,5*900(30^2-10^2)/1000)_{kinetic}+(900*10*(20-0)/1000)_{potential}\\E_{system,final}- E_{system,initial}=90+360+180=630kJ$

Consider that in the previous calculation, the kinetic and potential energy terms were divided by 1.000 to change the units from J to kJ.

Finally, the work needed to move the car under the required conditions is calculated as follows:

$W_{in}=Q_{out}+E_{system,final}- E_{system,initial}\\W_{in}=21,1011+630=651,1011kJ$

Consider that in the previous calculation, the heat loss was changed previously from BTU to kJ.

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3 years ago

A 1:50 scale model of a ship is towed at 4.8 km/hr using a force of 9 N. If we assume the same fluid in the model as in the prot

Mashutka [201]

Answer:

A: density and gravity

Explanation:

The Froude Number is defined as a dimensionless parameter that measures the ratio of the force of inertia on an element of fluid to the weight of the fluid element. In simple terms, it's the force of inertia divided by the gravitational force.

Froudes number is usually expressed as;

Fr = v/√(gd)

Where;

Fr = froude number

v = velocity

g = gravitational acceleration = specific weight/density

d = depth of flow

Now, to calculate the corresponding speed and force in the prototype, it means we have to use equal froude number and thus this will mean that it has to be dominated by gravity and density.

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3 years ago

An elastic cable is to be designed for bungee jumping from a tower 130 ft high. The specifications call for the cable to be 85 f

azamat

Answer:

a) The spring constant is 50 lb/ft

b) The man is 26.3 ft close to the ground.

Explanation:

Height of tower is 130 ft

Specification calls for a cable of length 85 ft

the maximum this length stretches is 100 ft when subjected to a load of 750 lb

The extension of the cable is calculated from the formula from Hooke's law

F = kx

where F is the load or force on the cable

k is the spring constant of the cable

x is the extension on the cable

a) The extension on the cable is

x = 100 ft - 85 ft = 15 ft

substituting into the formula above, we'll have

750 = k*15

k = 750/15 = 50 lb/ft

b) for a 185 lb man, jumping down will give an extension gotten as

F = kx

185 = 50*x

x = 185/50 = 3.7 ft

The total length of the cable will be extended to 100 ft + 3.7 ft = 103.7 ft

closeness to the ground = 130 ft - 103.7 ft = 26.3 ft

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3 years ago

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3 years ago