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Dahasolnce [82]
4 years ago
8

Consider the specific example of a positive charge q moving in the +x direction with the local magnetic field in the +y directio

n. In which direction is the magnetic force acting on the particle? Express your answer using unit vectors (e.g., i^- j^). (Recall that i^ is written \hat i (or alternatively i_unit can be used.))
Physics
2 answers:
OlgaM077 [116]4 years ago
7 0

Answer:

z+ direction

Explanation:

Imagine x+ and y+ as normal coordinate system on a paper. By using the right hand rule with thumb pointing to the direction of charge q moving (x+) and fingers pointing in the direction of the magnetic field (y+). The direction of the magnetic force would be coming out of your palm, or out of the paper surface in the z+ direction.

Leto [7]4 years ago
4 0

Answer:

Therefore the direction is in the <u>positive direction of the z axes</u>.

Explanation:

Let's recall that the magnetic force is given by:

F_{B}=q(\vec{v} \times \vec{B})

The unit vector of V is \hat{i} and the unit vector of B is \hat{j}

So, the direction of the force will be defined as the cross product of i and j, and using the right hand rule:

\hat{i} \times \hat{j} = \hat{z}

Therefore the direction of the magnetic force is in the <u>positive direction of the z axes</u>.

I hope it helps you!

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Answer:

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Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

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Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

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Now, from Newton's second law, net force equals mass times acceleration.

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Plug in the given values and solve for 'T'. This gives,

T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N

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