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Dahasolnce [82]
4 years ago
8

Consider the specific example of a positive charge q moving in the +x direction with the local magnetic field in the +y directio

n. In which direction is the magnetic force acting on the particle? Express your answer using unit vectors (e.g., i^- j^). (Recall that i^ is written \hat i (or alternatively i_unit can be used.))
Physics
2 answers:
OlgaM077 [116]4 years ago
7 0

Answer:

z+ direction

Explanation:

Imagine x+ and y+ as normal coordinate system on a paper. By using the right hand rule with thumb pointing to the direction of charge q moving (x+) and fingers pointing in the direction of the magnetic field (y+). The direction of the magnetic force would be coming out of your palm, or out of the paper surface in the z+ direction.

Leto [7]4 years ago
4 0

Answer:

Therefore the direction is in the <u>positive direction of the z axes</u>.

Explanation:

Let's recall that the magnetic force is given by:

F_{B}=q(\vec{v} \times \vec{B})

The unit vector of V is \hat{i} and the unit vector of B is \hat{j}

So, the direction of the force will be defined as the cross product of i and j, and using the right hand rule:

\hat{i} \times \hat{j} = \hat{z}

Therefore the direction of the magnetic force is in the <u>positive direction of the z axes</u>.

I hope it helps you!

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Setler79 [48]

Given Information:  

Voltage of circuit A = Va = 208 Volts

Current of circuit A = Ia = 40 Amps

Voltage of circuit B = Vb = 120 Volts

Current of circuit B = Ib = 20 Amps

Required Information:  

Ratio of power = Pa/Pb = ?

Answer:  

Ratio of power = Pa/Pb = 52/15

Explanation:  

Power can be calculated using Ohm's law

P = VI

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The power delivered by circuit B is

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Pb = 120*20

Pb = 2400 Watts

Therefore, the ratio of the maximum power delivered by circuit A to that delivered by circuit B is

Pa/Pb = 8320/2400

Pa/Pb = 52/15

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3 years ago
Objects falling through air experience a type Of friction called ____
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steposvetlana [31]

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Part A
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Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

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Using formula of momentum

p = mv

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Put the value into the formula

p=0.0073\times0.65

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Momentum of baseball = 3.14 kg m/s

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v=\dfrac{p}{m}

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v=\dfrac{3.14}{0.136}

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