Answer:
James Webb Space Telescope has 6.25 times the light collecting area than the mirror of Hubble Space Telescope.
Explanation:
Radius of Hubble Space Telescope mirror = 2.4/2 = 1.2 m
Radius of James Webb Space Telescope mirror = 6/2 = 3 m
Area of mirror of Hubble Space Telescope= πr² = π × 1.2² = 4.52 m²
Area of mirror of James Webb Space Telescope = π × 3² = 28.27 m²
Ratio of mirror area
[tex]\frac{A_J}{A_H}=\frac{28.27}{4.52}\\\Rightarrow A_J=6.25A_H[\tex]
mirror of James Webb Space Telescope has 6.25 times the area of mirror of Hubble Space Telescope.
Which means the James Webb Space Telescope has 6.25 times the light collecting area than the mirror of Hubble Space Telescope.
U=6.9ms-¹
a=0.62ms-²
t=3.4s
V=?
using
v=u+at
v=6.9+(0.62×3.4)
v= 6.9+2.108
v=9.008ms-¹
The answer is C) chemical potential energy. Fire is a chemical reaction.
As heat enters the surface of the Earth the gas traps it and is not radiated it's absorbed.
