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2 years ago

A student switches the torch on and sees that it gives out a bright light.

Physics

2 answers:

iVinArrow [24]2 years ago

7 0

Answer:

The fuel has ran out

Explanation:

Fuel could be Wood,cloth those are longer ones, theres also short term fuel sources such as gasoline, Cloth and wood are the most common for torches usually combined with alcohol, So either No more oxygen which is not likely, or the fuel source is running out

garik1379 [7]2 years ago

3 0

Answer:

no more fire duhh

Explanation:

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As an emergency vehicle approaches Bob and moves away from Jill, how does the actual frequency of the siren change? A) As an eme

Tamiku [17]

The correct answer is:
<span>C) The actual frequency of the siren does not change despite appearances.

In fact, Bob will observe an increase in the apparent frequency as the emergency vehicle approaches him, while Jill will observe a decrease in the apparent frequency as the emergency vehicle moves away from him, because of the Doppler effect (the relative velocity between the observer and the source of the sound is changing), but this effect involves the apparent frequency, while the real frequency of the siren will remain the same.</span>

7 0

2 years ago

Read 2 more answers

A man pushes on a piano with mass 190 kgkg ; it slides at constant velocity down a ramp that is inclined at 18.0 ∘∘ above the ho

creativ13 [48]

Answer:

The magnitude of applied force,parallel to the incline is 575.38 N and parallel to the floor is 605 N.

Explanation:

Given:

Mass of the piano $(m)$ = 190 kg

Inclined angle $(\theta)$ = 18 degree

Considering gravity, $g$ = 9.8 $ms^-^2$

And

Using, $sin(18) =0.30$ and $cos(18)=0.95$

<em>FBD diagram is attached with all the force acting on the floor and and the inclined. </em>

We have to find the magnitude of forces,when the man pushes it parallel to the incline and to the floor.

When the man pushes it parallel to the incline.

Balancing the forces as $\sum F=0$ .

⇒ $F+mgsin(\theta) =0$

⇒ $F=-mgsin(\theta)$

⇒ Here it is negative as the force is acting downward.

⇒ Plugging the values of mass $(m)$ and angle $(\theta)$ .

⇒ $F=190\times 9.8\times sin(18)$

⇒ $F=575.38$ N

When the force is parallel to the floor.

⇒ $Fcos(\theta)=mgsin(\theta)$

⇒ $F=\frac{mgsin(\theta)}{cos(\theta)}$

⇒ Plugging the values.

⇒ $F=\frac{190\times 9.8\times sin(18)}{cos(18)}$

⇒ $F=605$ N

So,

The magnitude of applied force in inclined direction is 575.38 Newton and parallel to the floor is 605 N.

6 0

2 years ago

What is an output force?

Vinil7 [7]

The answer would be D

5 0

2 years ago

Read 2 more answers

Compute the ratio of the rate of heat loss through a single-pane window with area 0.15 m2 to that for a double-pane window with

Rudik [331]

Answer:

2.80321285141

Explanation:

$L_g$ = Thickness of glass = 4.5 mm

$k_g$ = Thermal conductivity of glass = 0.8 W/mK

$R_0$ = Combined thermal resistance = $0.15\times m^2K/W$

$L_a$ = Thickness of air = 6.6 mm

$k_a$ = Thermal conductivity of air = 0.024 W/mK

The required ratio is the inverse of total thermal resistance

$\dfrac{2(L_g/k_g)+R_0+(L_a/k_a)}{(L_g/k_g)+R_0}\\ =\dfrac{2(4.5\times 10^{-3}/0.8)+0.15+(6.6\times 10^{-3}/0.024)}{(4.5\times 10^{-3}/0.8)+0.15}\\ =2.80321285141$

The ratio is 2.80321285141

4 0

3 years ago

Read 2 more answers

A box-shaped wood stove has dimensions of 0.75 mx 1.2 m x 0.4 m, an

Tresset [83]

Answer:

8.4 kW

Explanation:

Using the Stefan-Boltzmann law,

P = εAσT4

Where:

P: Radiation Energy

ε: Emissivity of the Surface. Check emissivity table below of common materials.

A: Surface Area, in m^2.

σ: Stefan-Boltzmann Constant, σ=5.67 × 10-8 W/m2•K4

T: Temperature

Plugging in values,

P = 0.85 x 3.328 x 5.67 x 10^(-8) x 205

P = 8383 W or 8.4 kW

3 0

3 years ago