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3 years ago

How much salt (NaCl) is carried by a river flowing at 30.0 m3/s and containing 50.0 mg/L of salt

Chemistry

1 answer:

denis23 [38]3 years ago

3 0

Answer:

129,600kg/day

Explanation:

The river is flowing at 30.0

1 m³ is equivalent to 1000L

flowrate of river = 30*1000 =30,000L/s

Convert L/s to litre per day by multiplying by 24*60*60

flowrate of river = 30,000 * 24*60*60 L/day

= 2,592,000,000L/day

if the river contains 50mg of salt in 1L of solution

lets find how many mg of salt Y is contained in 2,592,000,000L/day

by cross multiplying we have

Y= $\frac{2592000000*50}{1}$

Y= 129,600,000,000 mg/day

convert this value to kg/day by dividing by 1 million

Y= 129,600,000,000/1000000

Y= 129,600kg/day

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Cerrena [4.2K]

Answer:

C. 2-methylpropane

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There are rules guiding the naming of hydrocarbons. Some of the rules are:

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3 years ago

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Elena-2011 [213]

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2 years ago

Orange juice has a hydrogen ion concentration of approximately 10^-4. What is the pH of orange juice?

Yakvenalex [24]

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3 years ago

How many molecules are in 1.52 mol of dinitrogen monoxide

Natalka [10]

Answer:

9.15 × 10²³ molecules of N₂O present.

Explanation:

Given data:

number of moles = 1.52 mol

molar mass of N₂O = 44.013 g/mol

number of molecules = ?

Solution:

First of all we will calculate the mass of 1.52 mol.

mass = number of moles × molar mass

mass = 1.52 × 44.013 g/mol

mass = 66.9 g

Now we will find the number of molecules by using Avogadro number,

The number 6.022×10∧23 is called Avogadro number and it is the number of atoms or molecule in one gram atom of an element or one gram molecule of a compound.

44.013 g of N₂O = one mole of N₂O= 6.02 × 10²³ molecules

For 66.9 g:

66.9 g/ 44.013 g × 6.02 × 10²³ molecules

9.15 × 10²³ molecules of N₂O present

3 0

3 years ago