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andriy [413]
3 years ago
9

An atom has 3 protons, two electrons and 1 neutrons. Describe this atom using as many vocabulary words

Chemistry
1 answer:
andre [41]3 years ago
4 0

Answer: This is a very unstable atom. It is a cation, meaning it is positively charged. This atom doesn't have an equal amount of neutrons to protons, so it is extremely unstable. It has a charge of +1 because it is missing a negatively charged particle, making a positive charge.

Explanation:

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cupoosta [38]

Answer:

A

Explanation:

water molecules are combined to make food

5 0
3 years ago
When KNO3 dissolved in water, what is the intermolecular attraction between NO3 ions
Snezhnost [94]
Ion-dipole forces

H2O has hydrogen bonding, which is a form of dipole-dipole forces, and NO3- is an ion, so the intermolecular attraction is ion-dipole.
4 0
2 years ago
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Vladimir [108]
Note that it says oxygen "gas"
So you need the atomic mass of oxygen gas

Look at your periodic table, you'll see 15.9994 under oxygen
Oxygen gas has a formula of O2 therefore,
(15.9994) times 2= Oxygen gas atomic mass=31.9988

Mol= Mass/Atomic Mass
=62.3 g/ 31.9988 g/mol = 1.95 mol

now look at the ratio of C2H6 and O2, notice there is an invisible number beside each of them, at that "invisible number" is =1

1 C2H6 + 1 O2 -> products

this means that for 1 mol of C2H6, 1 mol of O2 has to react with it

Thus as we have 1.95 moles of O2, we need 1.95 moles of C2H6
5 0
3 years ago
Given K = 3.61 at 45°C for the reaction A(g) + B(g) equilibrium reaction arrow C(g) and K = 7.19 at 45°C for the reaction 2 A(g)
Firlakuza [10]

Answer:

K = 0.55

Kp = 0.55

mol fraction B = 0.27

Explanation:

We need to calculate the equilibrium constant for the reaction:

C(g) + D(g) ⇄ 2B(g)              K₁= ?                       (1)

and we are given the following equilibria with their respective Ks

A(g) + B(g) ⇄ C(g)                 K₂= 3.61                 (2)

2 A(g) + D(g)  ⇄ C(g)             K₃= 7.19                 (3)

all at 45 ºC.

What we need to do to solve this question is to manipulate equations (2) and (3)  algebraically  to get our desired equilibrium (1).

We are allowed to reverse  reactions, in that case we take the reciprocal of K as our new K' ; we can also  add two equilibria together, and the new equilibrium constant will be the product of their respective Ks .

Finally if we multiply by a number then we raise the old constant to that factor to get the new equilibrium constant.

With all this  in mind, lets try to solve our question.

Notice A is not in our goal equilibrium (3)  and we want D as a reactant . That  suggests we should reverse the first equilibria and multiply it by two since we have 2 moles of B  as product in our  equilibrium (1) . Finally we would add (2) and (3) to get  (1) which is our final  goal.

2C(g)             ⇄  2A(g) + 2B(g)  K₂´= ( 1/ 3.61 )²  

                                   ₊

2 A(g) + D(g)  ⇄     C(g)               K₃ = 7.19  

<u>                                                                                    </u>

C(g) + D(g)     ⇄    2B(g)       K₁ = ( 1/ 3.61 )²   x  7.19

                                             K₁ = 0.55

Kp is the same as K = 0.55 since the equilibrium constant expression only involves  gases.

To compute the last part lets setup the following mnemonic  ICE table to determine the quantities at equilibrium:

pressure (atm)        C             D           B

initial                     1.64          1.64         0

change                    -x             -x        +2x

equilibrium          1.64-x         1.64-       2x

Thus since

Kp =0.55 = pB²/ (pC x pD) = (2x)²/ (1.64 -x)²  where p= partial pressure

Taking square root to both sides of the equation we have

√0.55 = 2x/(1.64 - x)

solving for x  we obtain a value of 0.44 atm.

Thus at equilibrium we have:

(1.64 - 0.44) atm = 1.20 atm = pC = p D

2(0.44) = 0.88 = pB

mole fraction of B = partial pressure of B divided into the total gas pressure:

X(B) = 0.88 / ( 1.20 + 1.20 + 0.88 ) = 0.27

8 0
3 years ago
EASY Chemical reactions<br> Balance and classify
Marat540 [252]

Answer:

double replacement

synthesis

double replacement

i think this one is decomposition

synthesis

double replacement

single replacement

single replacement

double replacement

single replacement .....

hopefully i help

6 0
3 years ago
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