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Anna11 [10]
4 years ago
11

How does bohr's model differ from rutherford's model??

Chemistry
1 answer:
almond37 [142]4 years ago
3 0
Bohr suggested, that there are definitive shells of particular energy and angular momentum in which an electron can revolve. It was not in Rutherford's model
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How many liters are in a .00813M solution that contains 1.55 g of KBr?
Sloan [31]

Answer:

                      1.602 L (or) 1602 mL

Explanation:

             Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

                         Molarity  =  Moles / Volume of Solution    ----- (1)

Rearranging above equation for volume,

                         Volume of solution  =  Moles / Molarity    -------(2)

Data Given;

                  Molarity  =  0.00813 mol.L⁻¹

                  Mass  =  1.55 g

First calculate Moles for given mass as,

                   Moles  =  Mass / M.mass

                   Moles  =  1.55 g / 119.002 g.mol⁻¹

                   Moles  =  0.0130 mol

Now, putting value of Moles and Molarity in eq. 2,

                         Volume of solution  =  0.0130 mol / 0.00813 mol.L⁻¹

                         Volume of solution  = 1.60 L

or,

                         Volume of solution  =  1602 mL

5 0
3 years ago
What type of reaction is Pb(NO3)2 (aq) + 2KI (aq) →PbI2 + 2KNO3 (aq)
kifflom [539]

Answer:

Precipitation Reactions

They contain two aqueous reactants, one aqueous product, and one solid product. In this reaction, two soluble products, Pb(NO3)2 and KI, combine to form one soluble product, KNO3, and one insoluble product, PbI2. This is a precipitation reaction, and PbI2 is the precipitate.

4 0
3 years ago
1. The common name for the compound CH3-CH2-O-CH3 is ​
Ket [755]

Answer:

propane

Explanation:

please mark me as brainliest

3 0
3 years ago
Read 2 more answers
How many moles are in 2.00g of H2O​
gavmur [86]

n = m/M = 2/18 = 1/9 ~0,1 mol

4 0
2 years ago
Read 2 more answers
A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?
Stells [14]

by \: Charles'\: law: \:  \\  \frac{v_{1}}{t_{1}}  =  \frac{v_{2}}{t_{2}}  \\

Where v is the volume(in L) and t is the temperature(in °K)

\frac{8}{250}  =  \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}

7 0
2 years ago
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