Suppose you wanted to monitor a pH change between 5.3 and 6.3. Which indicator would be most appropriate?

Chemistry

2 answers:

umka2103 [35]3 years ago

7 0

It would be acidic based indicator.
0-6 is acidic
7 is neutral
8-14 is alkaline

alukav5142 [94]3 years ago

7 0

Answer:

d) bromothymol blue

Explanation:

Hello,

For that pH change between 5.3 and 6.3, we need an indicator which changes the color within that rank, in such a way, among the given options, one recalls the bromothymol blue because it turns yellow below about a pH of 6 and starts getting green above 6, therefore, one states that it is the most appropriated indicator.

Best regards.

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How many moles in 1.00g of salicylic acid?

salantis [7]

Answer:- 0.00724 moles.

Solution:- Grams of salicylic acid are given and it asks to calculate the moles.

For the moles, we divide the grams by the molar mass.

Formula of salicylic acid is $C_7H_6O_3$

Molar mass = 7(12.01)+6(1.01)+3(16.00)

= 84.07+6.06+48.00

= 138.13 gram per mol

We could make the dimensional analysis set up for showing unit cancellation and have the moles.

$1.00g(\frac{1mol}{138.13g})$

= 0.00724 moles

So, there will be 0.00724 moles of salicylic acid in it's 1.00 gram.

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3 years ago

13.50 grams of Pb(NO3)4 are dissolved in enough water to make 250 mL of solution. What is the molar its of the resulting solutio

likoan [24]

Data:
M (molarity) = ? (M or Mol/L)
m (mass) = 13.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass) of Lead(IV) Nitrate $Pb(NO_3)_4$
Pb = 1*207 = 207 amu
N = (1*14)*4 = 14*4 = 56 amu
O = (3*16)*4 = 48*4 = 192 amu
------------------------------------
MM of $Pb(NO_3)_4$ = 207+56+192 = 455 g/mol

Formula:
$M = \frac{m}{MM*V}$

Solving:
$M = \frac{m}{MM*V}$
$M = \frac{13.50}{455*0.25}$
$M = \frac{13.50}{113.75}$
$M = 0.118681318...\:\:\to\:\:\boxed{\boxed{M \approx 0.119\:Mol/L}}\end{array}}\qquad\quad\checkmark$

Answer:
<span>B. 0.119 M</span>

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3 years ago

draw the lewis structure for CO2, H2CO3, HCO3-, and CO3 2-.Rank these in order of increasing attraction to water molecules. Expl

gavmur [86]

Answer:

The structures are attached in file.

Hydrogen bonding and intermolecular forces is the reason for ranks allotted.

Explanation:

In determining Lewis structure, we calculate the overall number of valence electrons available for bonding. Making carbon (the least electronegative atom) the central atom in the structure, we allocate valence electrons until each atom has achieved stability.

In order of decreasing affinity to water molecules:

$CO_{3}^{2-} > HCO_{3} ^{2-} > H_{2} CO_{3}$

This is due to the fact that the $CO_{3}^{2-}$ will accept protons more readily than the bicarbonate ion, $HCO_{3} ^{2-}$ . Carbonic acid, $H_{2} CO_{3}$ will not accept any more protons, hence it is the least attractive to water molecule, even though soluble.