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a_sh-v [17]
3 years ago
5

If 52.5 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.248 g of precipitate, wh

at is the molarity of lead(II) ion in the original solution
Chemistry
1 answer:
user100 [1]3 years ago
7 0

Explanation:

The volume of given lead nitrate solution is:

52.5 mL.

The amount of lead iodide formed is ---0.248 g.

To get the molarity of lead (II) ion follow the below-shown procedure:

The number of moles of lead iodide formed is:

number of moles of lead iodide(n)=mass of lead iodide/its molecular mass\\n=0.248 g/461.01g/mol\\n=0.000537mol

0.000537 mole of lead iodide contains --- 0.000537 moles of lead (II) ion.

Thus, the number of moles are there, volume is there, and to get the molarity of lead (II) ion use the formula:

Molarity=\frac{number of moles}{volume in L.} \\M=0.000537 mol / 0.0525 L.\\M=0.0102mol/L

Molarity of lead iodide is --- 0.0102 M.

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Answer:

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A chemist measures the enthalpy change ?H during the following reaction: Fe (s) + 2HCl (g) ? FeCl2 (s) + H2 (g) =?H?157.kJ Use t
erik [133]

Correct Question:

A chemist measures the enthalpy change ΔH during the following reaction: Fe(s) + 2HCl(g)-->FeCl2(s) + H2 ΔH=-157.0 kJ. Use this information to complete the table below. Round each of your answers to the nearest kJ/mol

Answer:

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Explanation:

The enthalpy change of a reaction measures the amount of heat that is lost or gained by it. If ΔH >0 the heat is gained, and the reaction is called endothermic, if ΔH<0, the heat is lost, and the reaction is called exothermic.

If the reaction is inverted, the value of ΔH is inverted too (the opposite endothermic reaction is exothermic), and if the reaction is multiplied by a constant, ΔH will be multiplied by it too.

1) 2Fe(s) + 4HCl --> 2FeCl2(s) + 2H2(g)

This reaction is the product of the given reaction by 2, so

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3) FeCl2(s) + H2(g) --> Fe(s) + 2HCl

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